TS2531: Object is possibly 'null'

If you are sure that there is a file in all cases. You need make compiler to be sure.

(nativeElement.files as FileList)[0]

files is defined to be FileList | null so it can be null.

You should either check for null (using an if) or use a "Non-null assertion operator" (!) if you are sure it is not null:

if(nativeElement.files != null) {
    this.photoService.upload(this.vehicleId, nativeElement.files[0])
        .subscribe(x => console.log(x));
}

//OR
this.photoService.upload(this.vehicleId, nativeElement.files![0])
    .subscribe(x => console.log(x));

Note:

The "Non-null assertion operator" will not perform any runtime checks, it just tells the compiler you have special information and you know nativeElement.files will not be null at runtime.

If nativeElement.files is null at runtime, it will generate an error. This is not the safe navigation operator of other languages.

In addition to all the answers mentioned above, still if the user doesn't want the strict null checks in its application, we can just simply disable the strictNullChecks property in our tsconfig.json file.

{
 ...
 "angularCompilerOptions": {
 "strictNullChecks": false,
 ...
 }
}

TypeScript 3.7 got released in 11/2019. Now "Optional Chaining" is supported, this is the easiest and most secure way of working with potentially null-able values:

You simply write:

nativeElement?.file?.name

Note the Question-Mark! They check for null/undefined and only return the value, if none of the properties (chained with dots) is null/undefined.

Instead of

if(nativeElement!=null && nativeElement.file != null) {
  ....
}

But imagine something more complex like this: crm.contract?.person?.address?.city?.latlang that would otherwise a lot more verbose to check.