TypeScript for ... of with index / key?

.forEach already has this ability:

const someArray = [9, 2, 5];
someArray.forEach((value, index) => {
    console.log(index); // 0, 1, 2
    console.log(value); // 9, 2, 5
});

But if you want the abilities of for...of, then you can map the array to the index and value:

for (const { index, value } of someArray.map((value, index) => ({ index, value }))) {
    console.log(index); // 0, 1, 2
    console.log(value); // 9, 2, 5
}

That's a little long, so it may help to put it in a reusable function:

function toEntries<T>(a: T[]) {
    return a.map((value, index) => [index, value] as const);
}

for (const [index, value] of toEntries(someArray)) {
    // ..etc..
}

Iterable Version

This will work when targeting ES3 or ES5 if you compile with the --downlevelIteration compiler option.

function* toEntries<T>(values: T[] | IterableIterator<T>) {
    let index = 0;
    for (const value of values) {
        yield [index, value] as const;
        index++;
    }
}

Array.prototype.entries() - ES6+

If you are able to target ES6+ environments then you can use the .entries() method as outlined in Arnavion's answer.

See: Array.prototype.entries()

for (const [key, item] of someArray.entries()) { ... }

In TS this requires targeting ES2015 since it requires the runtime to support iterators, which ES5 runtimes don't. You can of course use something like Babel to make the output work on ES5 runtimes.

"Old school javascript" to the rescue (for those who aren't familiar/in love of functional programming)

for (let i = 0; i < someArray.length ; i++) {
  let item = someArray[i];
}