how to find the roots of a quadratic equation code example
Example 1: how to find roots of quadratic equation in c
#include <math.h>
#include <stdio.h>
int main() {
double a, b, c, discriminant, root1, root2, realPart, imagPart;
printf("Enter coefficients a, b and c: ");
scanf("%lf %lf %lf", &a, &b, &c);
discriminant = b * b - 4 * a * c;
if (discriminant > 0) {
root1 = (-b + sqrt(discriminant)) / (2 * a);
root2 = (-b - sqrt(discriminant)) / (2 * a);
printf("root1 = %.2lf and root2 = %.2lf", root1, root2);
}
else if (discriminant == 0) {
root1 = root2 = -b / (2 * a);
printf("root1 = root2 = %.2lf;", root1);
}
else {
realPart = -b / (2 * a);
imagPart = sqrt(-discriminant) / (2 * a);
printf("root1 = %.2lf+%.2lfi and root2 = %.2f-%.2fi", realPart, imagPart, realPart, imagPart);
}
return 0;
}
Example 2: Write a javascript program to find roots of quadratic equation.
let root1, root2;
let a = prompt("Enter the first number: ");
let b = prompt("Enter the second number: ");
let c = prompt("Enter the third number: ");
let discriminant = b * b - 4 * a * c;
if (discriminant > 0) {
root1 = (-b + Math.sqrt(discriminant)) / (2 * a);
root2 = (-b - Math.sqrt(discriminant)) / (2 * a);
console.log(`The roots of quadratic equation are ${root1} and ${root2}`);
}
else if (discriminant == 0) {
root1 = root2 = -b / (2 * a);
console.log(`The roots of quadratic equation are ${root1} and ${root2}`);
}
else {
let realPart = (-b / (2 * a)).toFixed(2);
let imagPart = (Math.sqrt(-discriminant) / (2 * a)).toFixed(2);
console.log(
`The roots of quadratic equation are ${realPart} + ${imagPart}i and ${realPart} - ${imagPart}i`
);
}