js get date difference code example
Example 1: javascript difference between two dates
const date1 = new Date('7/13/2010');
const date2 = new Date('12/15/2010');
console.log(getDifferenceInDays(date1, date2));
console.log(getDifferenceInHours(date1, date2));
console.log(getDifferenceInMinutes(date1, date2));
console.log(getDifferenceInSeconds(date1, date2));
function getDifferenceInDays(date1, date2) {
const diffInMs = Math.abs(date2 - date1);
return diffInMs / (1000 * 60 * 60 * 24);
}
function getDifferenceInHours(date1, date2) {
const diffInMs = Math.abs(date2 - date1);
return diffInMs / (1000 * 60 * 60);
}
function getDifferenceInMinutes(date1, date2) {
const diffInMs = Math.abs(date2 - date1);
return diffInMs / (1000 * 60);
}
function getDifferenceInSeconds(date1, date2) {
const diffInMs = Math.abs(date2 - date1);
return diffInMs / 1000;
}
Example 2: javascript difference between two dates in days
const diffDays = (date, otherDate) => Math.ceil(Math.abs(date - otherDate) / (1000 * 60 * 60 * 24));
diffDays(new Date('2014-12-19'), new Date('2020-01-01'));
Example 3: js calculate date difference
var DateDiff = {
inDays: function(d1, d2) {
var t2 = d2.getTime();
var t1 = d1.getTime();
return parseInt((t2-t1)/(24*3600*1000));
},
inWeeks: function(d1, d2) {
var t2 = d2.getTime();
var t1 = d1.getTime();
return parseInt((t2-t1)/(24*3600*1000*7));
},
inMonths: function(d1, d2) {
var d1Y = d1.getFullYear();
var d2Y = d2.getFullYear();
var d1M = d1.getMonth();
var d2M = d2.getMonth();
return (d2M+12*d2Y)-(d1M+12*d1Y);
},
inYears: function(d1, d2) {
return d2.getFullYear()-d1.getFullYear();
}
}
var dString = "May, 20, 1984";
var d1 = new Date(dString);
var d2 = new Date();
document.write("<br />Number of <b>days</b> since "+dString+": "+DateDiff.inDays(d1, d2));
document.write("<br />Number of <b>weeks</b> since "+dString+": "+DateDiff.inWeeks(d1, d2));
document.write("<br />Number of <b>months</b> since "+dString+": "+DateDiff.inMonths(d1, d2));
document.write("<br />Number of <b>years</b> since "+dString+": "+DateDiff.inYears(d1, d2));