restrict cout if the if-statement is c++ code example

Example 1: why does my if statement still run when the its not true c++

If the condition is true, result is set to 1, so much is true.
But in the other case, the content of result is undefined - 
so it can be anything,
even allowing the compiler to modify it at will as part of an 
optimization. 
You should either initialize result at its declaration,or add an else 
branch where you set it to the alternative value.

Example 2: if else program in c ++

// Program to check whether an integer is positive or negative
// This program considers 0 as a positive number

#include <iostream>
using namespace std;

int main() {
     int number;

    cout << "Enter an integer: ";
    cin >> number;
    if (number >= 0) {
        cout << "You entered a positive integer: " << number << endl;
    }
    else {
        cout << "You entered a negative integer: " << number << endl;
    }
    cout << "This line is always printed.";
    return 0;
}