Underscore is not working in oracle like clause

The other answers using the ESCAPE '\' didn't work for me, but I was able to overcome this issue by using a REPLACE function:

SELECT * FROM name_of_table WHERE REPLACE(description, '_', '~') LIKE 'testing~%';

try this in SQL Developer:

SELECT * FROM TABLE1 WHERE NAME LIKE 'test\_1%' escape '\'

in sql plus:

set escape '\'
SELECT * FROM TABLE1 WHERE NAME LIKE 'test\_1%';