Understanding JS Promises

Please check the below example regarding how promises works:

The Promise object represents the eventual completion (or failure) of an asynchronous operation, and its resulting value.

console.log('person1: shoe ticket');
console.log('person2: shoe ticket');

const promiseGirlFriendBringingTickets = new Promise((resolve, reject) => {
	setTimeout(() => {
		resolve('ticket');
	}, 3000);
});

promiseGirlFriendBringingTickets.then((t) => {
	console.log(`person3: show ${t}`);
})

console.log('person4: shoe ticket');
console.log('person5: shoe ticket');

Let's start with an easy perspective: "chainPromises" returns a promise, so you could look at it this way:

// Do all internal promises
var cp = chainPromises();

// After everything is finished you execute the final "then".
cp.then(function(val) {
    console.log(val);
});

Generally speaking, when returning a promise from within a "then" clause, the "then" function of the encapsulating promise will be marked as finished only after the internal "then" has finished.

So, if "a" is a promise, and "b" is a promise:

// "a"'s "then" function will only be marked as finished after "b"'s "then" function has finished.  
var c = a.then(function () {
    return b.then(function () {
        console.log("B!");
    };
};

// c is a promise, since "then" always returns a promise.    
c.then(function() {
    console.log("Done!");
};

So the output will be:

B! 
Done!

Notice btw, that if you don't "return" the internal promise, this will not be the case:

// "a"'s "then" function will only be marked as finished without waiting for "b"'s "then" to finish.  
var c = a.then(function () {
    // Notice we're just calling b.then, and don't "return" it. 
    b.then(function () {
        console.log("B!");
    };
};

// c is a promise, since "then" always returns a promise.    
c.then(function() {
    console.log("Done!");
};

Here we can't know what would be outputted first. It could be either "B!" or "Done!".

About Promise resolution

The thing you're witnessing here is called recursive thenable resolution. The promise resolution process in the Promises/A+ specification contains the following clause:

onFulfilled or onRejected returns a value x, run the Promise Resolution Procedure [[Resolve]](promise2, x)

The ES6 promise specification (promises unwrapping) contains a similar clause.

This mandates that when a resolve operation occurs: either in the promise constructor, by calling Promise.resolve or in your case in a then chain a promise implementation must recursively unwrap the returned value if it is a promise.

In practice

This means that if onFulfilled (the then) returns a value, try to "resolve" the promise value yourself thus recursively waiting for the entire chain.

This means the following:

promiseReturning().then(function(){
    alert(1);
    return foo(); // foo returns a promise
}).then(function(){
    alert(2); // will only run after the ENTIRE chain of `foo` resolved
              // if foo OR ANY PART OF THE CHAIN rejects and it is not handled this 
              // will not run
});

So for example:

promiseReturning().then(function(){
    alert(1);
    return Promise.resolve().then(function(){ throw Error(); });
}).then(function(){
    alert("This will never run");
});

And that:

promiseReturning().then(function(){
    alert(1);
    return Promise.resolve().then(function(){ return delay(2000); });
}).then(function(){
    alert("This will only run after 2000 ms");
});

Is it a good idea?

It's been the topic of much debate in the promises specification process a second chain method that does not exhibit this behavior was discussed but decided against (still available in Chrome, but will be removed soon). You can read about the whole debate in this esdiscuss thread. This behavior is for pragmatic reasons so you wouldn't have to manually do it.

In other languages

It's worth mentioning that other languages do not do this, neither futures in Scala or tasks in C# have this property. For example in C# you'd have to call Task.Unwrap on a task in order to wait for its chain to resolve.