Unpack python tuple with [ ]'s
I have checked the execution time and number of cycles using Linux perf tools. All 3 programs are showing the same execution time, so I think there are not any extra costs.
No, those are all exactly equivalent. One way to look at this empirically is to use the dis
dissasembler:
>>> import dis
>>> dis.dis("a, b, c = (1, 2, 3)")
1 0 LOAD_CONST 0 ((1, 2, 3))
2 UNPACK_SEQUENCE 3
4 STORE_NAME 0 (a)
6 STORE_NAME 1 (b)
8 STORE_NAME 2 (c)
10 LOAD_CONST 1 (None)
12 RETURN_VALUE
>>> dis.dis("(a, b, c) = (1, 2, 3)")
1 0 LOAD_CONST 0 ((1, 2, 3))
2 UNPACK_SEQUENCE 3
4 STORE_NAME 0 (a)
6 STORE_NAME 1 (b)
8 STORE_NAME 2 (c)
10 LOAD_CONST 1 (None)
12 RETURN_VALUE
>>> dis.dis("[a, b, c] = (1, 2, 3)")
1 0 LOAD_CONST 0 ((1, 2, 3))
2 UNPACK_SEQUENCE 3
4 STORE_NAME 0 (a)
6 STORE_NAME 1 (b)
8 STORE_NAME 2 (c)
10 LOAD_CONST 1 (None)
12 RETURN_VALUE
>>>
From the formal language specification, this is detailed here. This is part of the "target list", A relevant quote:
Assignment of an object to a target list, optionally enclosed in parentheses or square brackets, is recursively defined as follows....
Using godbolt and selecting Python
as the language then entering the three lines of code, you can see they all have the same bytecode:
1 0 LOAD_CONST 5 ((1, 2, 3))
2 UNPACK_SEQUENCE 3
4 STORE_NAME 0 (a)
6 STORE_NAME 1 (b)
8 STORE_NAME 2 (c)
2 10 LOAD_CONST 6 ((1, 2, 3))
12 UNPACK_SEQUENCE 3
14 STORE_NAME 0 (a)
16 STORE_NAME 1 (b)
18 STORE_NAME 2 (c)
3 20 LOAD_CONST 7 ((1, 2, 3))
22 UNPACK_SEQUENCE 3
24 STORE_NAME 0 (a)
26 STORE_NAME 1 (b)
28 STORE_NAME 2 (c)
So, they are the same, just different syntaxes.