Unzip all zipped files in a folder to that same folder using Python 2.7.5
I think this is shorter and worked fine for me. First import the modules required:
import zipfile, os
Then, I define the working directory:
working_directory = 'my_directory'
os.chdir(working_directory)
After that you can use a combination of the os
and zipfile
to get where you want:
for file in os.listdir(working_directory): # get the list of files
if zipfile.is_zipfile(file): # if it is a zipfile, extract it
with zipfile.ZipFile(file) as item: # treat the file as a zip
item.extractall() # extract it in the working directory
Below is the code that worked for me:
import os, zipfile
dir_name = 'C:\\SomeDirectory'
extension = ".zip"
os.chdir(dir_name) # change directory from working dir to dir with files
for item in os.listdir(dir_name): # loop through items in dir
if item.endswith(extension): # check for ".zip" extension
file_name = os.path.abspath(item) # get full path of files
zip_ref = zipfile.ZipFile(file_name) # create zipfile object
zip_ref.extractall(dir_name) # extract file to dir
zip_ref.close() # close file
os.remove(file_name) # delete zipped file
Looking back at the code I had amended, the directory was getting confused with the directory of the script.
The following also works while not ruining the working directory. First remove the line
os.chdir(dir_name) # change directory from working dir to dir with files
Then assign file_name as
file_name = dir_name + "/" + item
The accepted answer works great!
Just to extend the idea to unzip all the files with .zip extension within all the sub-directories inside a directory the following code seems to work well:
import os
import zipfile
for path, dir_list, file_list in os.walk(dir_path):
for file_name in file_list:
if file_name.endswith(".zip"):
abs_file_path = os.path.join(path, file_name)
# The following three lines of code are only useful if
# a. the zip file is to unzipped in it's parent folder and
# b. inside the folder of the same name as the file
parent_path = os.path.split(abs_file_path)[0]
output_folder_name = os.path.splitext(abs_file_path)[0]
output_path = os.path.join(parent_path, output_folder_name)
zip_obj = zipfile.ZipFile(abs_file_path, 'r')
zip_obj.extractall(output_path)
zip_obj.close()