upload image and display using php code example

Example 1: how to upload image in php and store in database and folder

// Get the name of images
  	$Get_image_name = $_FILES['image']['name'];
  	
  	// image Path
  	$image_Path = "images/".basename($Get_image_name);

  	$sql = "INSERT INTO student_table (imagename, contact) VALUES ('$Get_image_name', 'USA')";
  	
	// Run SQL query
  	mysqli_query($conn, $sql);

  	if (move_uploaded_file($_FILES['image']['tmp_name'], $image_Path)) {
  		echo "Your Image uploaded successfully";
  	}else{
  		echo  "Not Insert Image";
  	}
  }

Example 2: php upload file

<?php
   if(isset($_FILES['image'])){
      $errors= array();
      $file_name = $_FILES['image']['name'];
      $file_size =$_FILES['image']['size'];
      $file_tmp =$_FILES['image']['tmp_name'];
      $file_type=$_FILES['image']['type'];
      $file_ext=strtolower(end(explode('.',$_FILES['image']['name'])));
      
      $extensions= array("jpeg","jpg","png");
      
      if(in_array($file_ext,$extensions)=== false){
         $errors[]="extension not allowed, please choose a JPEG or PNG file.";
      }
      
      if($file_size > 2097152){
         $errors[]='File size must be excately 2 MB';
      }
      
      if(empty($errors)==true){
         move_uploaded_file($file_tmp,"images/".$file_name);
         echo "Success";
      }else{
         print_r($errors);
      }
   }
?>

Example 3: php image upload in database

<?php
error_reporting(0);
?>
<?php
$msg = "";

// If upload button is clicked ...
if (isset($_POST['upload'])) {

	$filename = $_FILES["uploadfile"]["name"];
	$tempname = $_FILES["uploadfile"]["tmp_name"];
		$folder = "image/".$filename;

	$db = mysqli_connect("localhost", "root", "", "image_upload");

		// Get all the submitted data from the form
		$sql = "INSERT INTO images (filename) VALUES ('$filename')";

		// Execute query
		mysqli_query($db, $sql);

		// Now let's move the uploaded image into the folder: image
		if (move_uploaded_file($tempname, $folder)) {
			$msg = "Image uploaded successfully";
		}else{
			$msg = "Failed to upload image";
	}
}
$result = mysqli_query($db, "SELECT * FROM images");
?>

<!DOCTYPE html>
<html>
<head>
<title>Image Upload</title>
<link rel="stylesheet" type= "text/css" href ="style.css"/>
<div id="content">

<form method="POST" action="" enctype="multipart/form-data">
	<input type="file" name="uploadfile" value=""/>

	<div>
		<button type="submit" name="upload">UPLOAD</button>
		</div>
</form>
</div>
</body>
</html>

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