Use Python to launch Excel file
Just these two lines
import os
os.system("start EXCEL.EXE file.xlsx")
Provided that file.xlsx is in the current directory.
I don't know about Mac OS, but if Windows Operating System is the case and provided the Microsoft Windows is properly installed, then consider using :
import os
os.system('start "excel" "C:\\path\\to\\myfile.xlsx"')
double-quotation
is important for excel
and C:\\path\\to\\myfile.xlsx
( where C
just denotes the letter for the partition within the file system, might be replaced by D
,E
..etc. ), and single-quotation
is needed for the whole string within the os.system()
.
If you only want to open the excel application you could use subprocess:
import subprocess
subprocess.check_call(['open', '-a', 'Microsoft Excel'])
You can also use os and open a specific file:
import os
os.system("open -a 'path/Microsoft Excel.app' 'path/file.xlsx'")
If you on other hand want to open an excel file within python and modify it there's a number of packages to use as xlsxwriter, xlutils and openpyxl where the latter is prefered by me.
Another note, if you're on mac the excel application isn't .exe