Using 'find' to return filenames without extension
Here's a simple solution:
find . -type f -iname "*.ipynb" | sed 's/\.ipynb$//1'
To return only filenames without the extension, try:
find . -type f -iname "*.ipynb" -execdir sh -c 'printf "%s\n" "${0%.*}"' {} ';'
or (omitting -type f
from now on):
find "$PWD" -iname "*.ipynb" -execdir basename {} .ipynb ';'
or:
find . -iname "*.ipynb" -exec basename {} .ipynb ';'
or:
find . -iname "*.ipynb" | sed "s/.*\///; s/\.ipynb//"
however invoking basename
on each file can be inefficient, so @CharlesDuffy suggestion is:
find . -iname '*.ipynb' -exec bash -c 'printf "%s\n" "${@%.*}"' _ {} +
or:
find . -iname '*.ipynb' -execdir basename -s '.sh' {} +
Using +
means that we're passing multiple files to each bash instance, so if the whole list fits into a single command line, we call bash only once.
To print full path and filename (without extension) in the same line, try:
find . -iname "*.ipynb" -exec sh -c 'printf "%s\n" "${0%.*}"' {} ';'
or:
find "$PWD" -iname "*.ipynb" -print | grep -o "[^\.]\+"
To print full path and filename on separate lines:
find "$PWD" -iname "*.ipynb" -exec dirname "{}" ';' -exec basename "{}" .ipynb ';'