Using PHP Replace SPACES in URLS with %20

No need for a regex here, if you just want to replace a piece of string by another: using str_replace() should be more than enough :

$new = str_replace(' ', '%20', $your_string);

But, if you want a bit more than that, and you probably do, if you are working with URLs, you should take a look at the urlencode() function.

I think you must use rawurlencode() instead urlencode() for your purpose.

sample

$image = 'some images.jpg';
$url   = 'http://example.com/'

With urlencode($str) will result

echo $url.urlencode($image); //http://example.com/some+images.jpg

its not change to %20 at all

but with rawurlencode($image) will produce

echo $url.rawurlencode(basename($image)); //http://example.com/some%20images.jpg

Use urlencode() rather than trying to implement your own. Be lazy.

You've got several options how to do this, either:

urlencode() or rawurlencode() - functions designed to encode URLs for http protocol
str_replace() - "heavy machinery" string replace
strtr() - would have better performance than str_replace() when replacing multiple characters
preg_replace() use regular expressions (perl compatible)

Assuming that you want to replace "\t" and " " with "%20":

$replace_pairs = array(
  "\t" => '%20',
  " " => '%20',
);
return strtr( $text, $replace_pairs)

You've got few options here, either replacing just space ~ ~, again replacing space and tab ~[ \t]~ or all kinds of spaces ~\s~:

return preg_replace( '~\s~', '%20', $text);

Or when you need to replace string like this "\t \t \t \t" with just one %20:

return preg_replace( '~\s+~', '%20', $text);

_{I assumed that you really want to use manual string replacement and handle more types of whitespaces such as non breakable space ( )}

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