Using spread syntax and new Set() with typescript

You can also use Array.from method to convert the Set to Array

let uniques = Array.from(new Set([1, 2, 3, 1, 1])) ;
console.log(uniques);

This is a missing feature. TypeScript only supports iterables on Arrays at the moment.

Update: With Typescript 2.3, you can now add "downlevelIteration": true to your tsconfig, and this will work while targeting ES5.

The downside of downlevelIteration is that TS will have to inject quite a bit of boilerplate when transpiling. The single line from the question transpiles with 21 lines of added boilerplate: (as of Typescript 2.6.1)

var __read = (this && this.__read) || function (o, n) {
    var m = typeof Symbol === "function" && o[Symbol.iterator];
    if (!m) return o;
    var i = m.call(o), r, ar = [], e;
    try {
        while ((n === void 0 || n-- > 0) && !(r = i.next()).done) ar.push(r.value);
    }
    catch (error) { e = { error: error }; }
    finally {
        try {
            if (r && !r.done && (m = i["return"])) m.call(i);
        }
        finally { if (e) throw e.error; }
    }
    return ar;
};
var __spread = (this && this.__spread) || function () {
    for (var ar = [], i = 0; i < arguments.length; i++) ar = ar.concat(__read(arguments[i]));
    return ar;
};
var uniques = __spread(new Set([1, 2, 3, 1, 1]));
console.log(uniques);

This boilerplate will be injected once per file that uses downlevel iteration, and this boilerplate can be reduced using the "importHelpers" option via the tsconfig. (See this blogpost on downlevel iteration and importHelpers)

Alternatively, if ES5 support doesn't matter for you, you can always just target "es6" in the first place, in which case the original code works without needing the "downlevelIteration" flag.

Original answer:

This seems to be a typescript ES6 transpilation quirk . The ... operator should work on anything that has an iterator property, (Accessed by obj[Symbol.iterator]) and Sets have that property.

To work around this, you can use Array.from to convert the set to an array first: ...Array.from(new Set([1, 2, 3, 1, 1])).