using sql count in a case statement
Close... try:
select
Sum(case when rsp_ind = 0 then 1 Else 0 End) as 'New',
Sum(case when rsp_ind = 1 then 1 else 0 end) as 'Accepted'
from tb_a
SELECT
COUNT(CASE WHEN rsp_ind = 0 then 1 ELSE NULL END) as "New",
COUNT(CASE WHEN rsp_ind = 1 then 1 ELSE NULL END) as "Accepted"
from tb_a
You can see the output for this request HERE
Depending on you flavor of SQL, you can also imply the else statement in your aggregate counts.
For example, here's a simple table Grades
:
| Letters |
|---------|
| A |
| A |
| B |
| C |
We can test out each Aggregate counter syntax like this (Interactive Demo in SQL Fiddle):
SELECT
COUNT(CASE WHEN Letter = 'A' THEN 1 END) AS [Count - End],
COUNT(CASE WHEN Letter = 'A' THEN 1 ELSE NULL END) AS [Count - Else Null],
COUNT(CASE WHEN Letter = 'A' THEN 1 ELSE 0 END) AS [Count - Else Zero],
SUM(CASE WHEN Letter = 'A' THEN 1 END) AS [Sum - End],
SUM(CASE WHEN Letter = 'A' THEN 1 ELSE NULL END) AS [Sum - Else Null],
SUM(CASE WHEN Letter = 'A' THEN 1 ELSE 0 END) AS [Sum - Else Zero]
FROM Grades
And here are the results (unpivoted for readability):
| Description | Counts |
|-------------------|--------|
| Count - End | 2 |
| Count - Else Null | 2 |
| Count - Else Zero | 4 | *Note: Will include count of zero values
| Sum - End | 2 |
| Sum - Else Null | 2 |
| Sum - Else Zero | 2 |
Which lines up with the docs for Aggregate Functions in SQL
Docs for COUNT
:
COUNT(*)
- returns the number of items in a group. This includes NULL values and duplicates.COUNT(ALL expression)
- evaluates expression for each row in a group, and returns the number of nonnull values.COUNT(DISTINCT expression)
- evaluates expression for each row in a group, and returns the number of unique, nonnull values.
Docs for SUM
:
ALL
- Applies the aggregate function to all values. ALL is the default.DISTINCT
- Specifies that SUM return the sum of unique values.