Using the passwd command from within a shell script

The only solution works on Ubuntu 12.04:

echo -e "new_password\nnew_password" | (passwd user)

But the second option only works when I change from:

echo "password:name" | chpasswd

To:

echo "user:password" | chpasswd

See explanations in original post: Changing password via a script

Read the wise words from:

• http://mywiki.wooledge.org/BashFAQ/078

I quote:

Nothing you can do in bash can possibly work. passwd(1) does not read from standard input. This is intentional. It is for your protection. Passwords were never intended to be put into programs, or generated by programs. They were intended to be entered only by the fingers of an actual human being, with a functional brain, and never, ever written down anywhere.

Nonetheless, we get hordes of users asking how they can circumvent 35 years of Unix security.

It goes on to explain how you can set your shadow(5) password properly, and shows you the GNU-I-only-care-about-security-if-it-doesn't-make-me-think-too-much-way of abusing passwd(1).

Lastly, if you ARE going to use the silly GNU passwd(1) extension --stdin, do not pass the password putting it on the command line.

echo $mypassword | passwd --stdin # Eternal Sin.
echo "$mypassword" | passwd --stdin # Eternal Sin, but at least you remembered to quote your PE.
passwd --stdin <<< "$mypassword" # A little less insecure, still pretty insecure, though.
passwd --stdin < "passwordfile" # With a password file that was created with a secure `umask(1)`, a little bit secure.

The last is the best you can do with GNU passwd. Though I still wouldn't recommend it.

Putting the password on the command line means anyone with even the remotest hint of access to the box can be monitoring ps or such and steal the password. Even if you think your box is safe; it's something you should really get in the habit of avoiding at all cost (yes, even the cost of doing a bit more trouble getting the job done).

from "man 1 passwd":

   --stdin
          This option is used to indicate that passwd should read the new
          password from standard input, which can be a pipe.

So in your case

adduser "$1"
echo "$2" | passwd "$1" --stdin

[Update] a few issues were brought up in the comments:

Your passwd command may not have a --stdin option: use the chpasswd utility instead, as suggested by ashawley.

If you use a shell other than bash, "echo" might not be a builtin command, and the shell will call /bin/echo. This is insecure because the password will show up in the process table and can be seen with tools like ps.

In this case, you should use another scripting language. Here is an example in Perl:

#!/usr/bin/perl -w
open my $pipe, '|chpasswd' or die "can't open pipe: $!";
print {$pipe} "$username:$password";
close $pipe

Nowadays, you can use this command:

echo "user:pass" | chpasswd