excel vba are bits set in long code example
Example 1: excel vba are bits set in long
'Fast VBA function to test if specific bits are set
'within a 32-bit Long integer. If ALL specified bits are set then
'this function returns True. If ANY of the specified bits are
'not set then this function returns False.
'Bits are numbered from 0 to 31, so the first (least significant) bit
'is bit 0.
'Note: bits can be specified in any order.
'Note: any number of bits can be specified in one call.
Function LongBitsAreSet(theLong&, ParamArray bits()) As Boolean
Static i&, b&()
If UBound(bits) = -1 Then Exit Function
If (Not Not b) = 0 Then
ReDim b(0 To 30)
For i = 0 To 30
b(i) = 2 ^ i
Next
End If
For i = 0 To UBound(bits)
If bits(i) < 0 Then Exit Function
If bits(i) > 30 Then Exit Function
If (theLong And b(Int(bits(i)))) = 0 Then Exit Function
Next
LongBitsAreSet = True
End Function
'---------------------------------------------------------------------------------------------------------------------
MsgBox LongBitsAreSet(255, 7) '<--displays: True 255 = 00000000 00000000 00000000 11111111
MsgBox LongBitsAreSet(230, 0) '<--displays: False 230 = 00000000 00000000 00000000 11100110
MsgBox LongBitsAreSet(85, 0, 2, 6, 4) '<--displays: True 85 = 00000000 00000000 00000000 01010101
MsgBox LongBitsAreSet(85, 0, 2, 5, 4) '<--displays: False 85 = 00000000 00000000 00000000 01010101
MsgBox LongBitsAreSet(485, 2, 7, 5) '<--displays: True 485 = 00000000 00000000 00000001 11100101
MsgBox LongBitsAreSet(24585, 14, 13, 3) '<--displays: True 24585 = 00000000 00000000 01100000 00001001
MsgBox LongBitsAreSet(&H7D12EACB, 24, 26, 30, 7) '<--displays: True 2098391755 = 01111101 00010010 11101010 11001011
'
'
'Example 2: excel vba are bits set in integer
'Fast VBA function to test if specific bits are set
'within a 16-bit Integer. If ALL specified bits are set then
'this function returns True. If ANY of the specified bits are
'not set then this function returns False.
'Bits are numbered from 0 to 15, so the first (least significant) bit
'is bit 0.
'Note: bits can be specified in any order.
'Note: any number of bits can be specified in one call.
Function IntegerBitsAreSet(theInteger%, ParamArray bits()) As Boolean
Static i&, b%()
If UBound(bits) = -1 Then Exit Function
If (Not Not b) = 0 Then
ReDim b(0 To 14)
For i = 0 To 14
b(i) = 2 ^ i
Next
End If
For i = 0 To UBound(bits)
If bits(i) < 0 Then Exit Function
If bits(i) > 14 Then Exit Function
If (theInteger And b(Int(bits(i)))) = 0 Then Exit Function
Next
IntegerBitsAreSet = True
End Function
'----------------------------------------------------------------------------------------
MsgBox IntegerBitsAreSet(255, 7) '<--displays: True 255 = 00000000 11111111
MsgBox IntegerBitsAreSet(230, 0) '<--displays: False 230 = 00000000 11100110
MsgBox IntegerBitsAreSet(85, 0, 2, 6, 4) '<--displays: True 85 = 00000000 01010101
MsgBox IntegerBitsAreSet(85, 0, 2, 5, 4) '<--displays: False 85 = 00000000 01010101
MsgBox IntegerBitsAreSet(485, 2, 7, 5) '<--displays: True 485 = 00000001 11100101
MsgBox IntegerBitsAreSet(24585, 14, 13, 3) '<--displays: True 24585 = 01100000 00001001
'
'
'Example 3: excel vba are bits set in byte
'Fast VBA function to test if specific bits are set
'within a Byte. If ALL specified bits are set then this function
'returns True. If ANY of the specified bits are not set then
'this function returns False.
'Bits are numbered from 0 to 7, so the first (least significant) bit
'is bit 0.
'Note: bits can be specified in any order.
Function ByteBitsAreSet(theByte As Byte, ParamArray bits()) As Boolean
Static i&, b() As Byte
If UBound(bits) = -1 Then Exit Function
If (Not Not b) = 0 Then
ReDim b(0 To 7)
For i = 0 To 7
b(i) = 2 ^ i
Next
End If
For i = 0 To UBound(bits)
If bits(i) < 0 Then Exit Function
If bits(i) > 7 Then Exit Function
If (theByte And b(Int(bits(i)))) = 0 Then Exit Function
Next
ByteBitsAreSet = True
End Function
'--------------------------------------------------------------------------
MsgBox ByteBitsAreSet(255, 7) '<--displays: True 255 = 11111111
MsgBox ByteBitsAreSet(230, 0) '<--displays: False 230 = 11100110
MsgBox ByteBitsAreSet(85, 0, 2, 6, 4) '<--displays: True 85 = 01010101
MsgBox ByteBitsAreSet(85, 0, 2, 5, 4) '<--displays: False 85 = 01010101
'
'
'Example 4: excel vba is bit set long
'Extremely fast VBA function to test if a specified bit is set
'within a 32-bit Long integer.
'Bits are numbered from 0 to 31, so the first (least significant) bit
'is bit 0.
'Note: we do not inspect bit 31, the sign bit.
'Note: any number of bits can be specified in one call.
Function LongBitIsSet(theLong&, bit As Byte) As Boolean
Static i&, b&()
If (Not Not b) = 0 Then
ReDim b(0 To 30)
For i = 0 To 30
b(i) = 2 ^ i
Next
End If
If bit < 31 Then LongBitIsSet = theLong And b(bit)
End Function
'------------------------------------------------------------------
MsgBox LongBitIsSet(255, 7) '<--displays: True
MsgBox LongBitIsSet(230, 0) '<--displays: False
MsgBox LongBitIsSet(16384, 14) '<--displays: True
MsgBox LongBitIsSet(-16383, 0) '<--displays: True
MsgBox LongBitIsSet(&H7FFFFFFF, 0) '<--displays: TrueExample 5: excel vba set bit in byte
'Extremely fast VBA function to test if a specified bit is set
'within a Byte.
'Bits are numbered from 0 to 7, so the first (least significant) bit
'is bit 0.
Function ByteBitIsSet(theByte As Byte, bit As Byte) As Boolean
Static i&, b() As Byte
If (Not Not b) = 0 Then
ReDim b(0 To 7)
For i = 0 To 7
b(i) = 2 ^ i
Next
End If
If bit < 8 Then ByteBitIsSet = theByte And b(bit)
End Function
'------------------------------------------------------------------
MsgBox ByteBitIsSet(255, 7) '<--displays: True
MsgBox ByteBitIsSet(230, 0) '<--displays: False