excel vba check if specific bits set in 64-bit longlong integer code example
Example 1: vba long integer value to bits
Function LongToBits$(ByVal n&)
Dim i&
LongToBits = "00000000000000000000000000000000"
If n And &H80000000 Then
Mid$(LongToBits, 1, 1) = "1"
n = n And Not &H80000000
End If
For i = 32 To 2 Step -1
If n And 1 Then Mid$(LongToBits, i, 1) = "1"
n = n \ 2
Next
End Function
'------------------------------------------------------------------------------
MsgBox LongToBits(0) '<--displays: 00000000000000000000000000000000
MsgBox LongToBits(293781237) '<--displays: 00010001100000101011111011110101
MsgBox LongToBits(-1) '<--displays: 11111111111111111111111111111111Example 2: vba test if particular bits set in longlong integer
'Fast VBA function to test if specific bits are set
'within a 64-bit LongLong integer. If ALL specified bits are set then
'this function returns True. If ANY of the specified bits are
'not set then this function returns False.
'Bits are numbered from 0 to 63, so the first (least significant) bit
'is bit 0.
'Note: bits can be specified in any order.
'Note: any number of bits can be specified in one call.
'Note: the LongLong data type is only available in 64-bit VBA.
Function LongLongBitsAreSet(theLongLong^, ParamArray bits()) As Boolean
Static i&, b^()
If UBound(bits) = -1 Then Exit Function
If (Not Not b) = 0 Then
ReDim b(0 To 62)
For i = 0 To 62
b(i) = 2 ^ i
Next
End If
For i = 0 To UBound(bits)
If bits(i) < 0 Then Exit Function
If bits(i) > 62 Then Exit Function
If (theLongLong And b(Int(bits(i)))) = 0 Then Exit Function
Next
LongLongBitsAreSet = True
End Function
'----------------------------------------------------------------------------------------------------------------------------------------------------------------------
MsgBox LongLongBitsAreSet(255, 7) '<--displays: True 255 = 00000000 00000000 00000000 00000000 00000000 00000000 00000000 11111111
MsgBox LongLongBitsAreSet(230, 0) '<--displays: False 230 = 00000000 00000000 00000000 00000000 00000000 00000000 00000000 11100110
MsgBox LongLongBitsAreSet(85, 0, 2, 6, 4) '<--displays: True 85 = 00000000 00000000 00000000 00000000 00000000 00000000 00000000 01010101
MsgBox LongLongBitsAreSet(85, 0, 2, 5, 4) '<--displays: False 85 = 00000000 00000000 00000000 00000000 00000000 00000000 00000000 01010101
MsgBox LongLongBitsAreSet(485, 2, 7, 5) '<--displays: True 485 = 00000000 00000000 00000000 00000000 00000000 00000000 00000001 11100101
MsgBox LongLongBitsAreSet(24585, 14, 13, 3) '<--displays: True 24585 = 00000000 00000000 00000000 00000000 00000000 00000000 01100000 00001001
MsgBox LongLongBitsAreSet(&H7D12EACB, 24, 26, 30, 7) '<--displays: True 2098391755 = 00000000 00000000 00000000 00000000 01111101 00010010 11101010 11001011
MsgBox LongLongBitsAreSet(2 ^ 62 + 1, 62, 0) '<--displays: True 4611686018427387905 = 01000000 00000000 00000000 00000000 00000000 00000000 00000000 00000001
'
'
'Example 3: xl vba is specific bit set in longlong integer
'Extremely fast VBA function to test if a specified bit is set
'within a 64-bit LongLong integer.
'Bits are numbered from 0 to 63, so the first (least significant) bit
'is bit 0.
'Note: we do not inspect bit 63, the sign bit.
'Note: the LongLong data type is only available in 64-bit VBA.
Function LongLongBitIsSet(theLongLong^, bit As Byte) As Boolean
Static i&, b^()
If (Not Not b) = 0 Then
ReDim b(0 To 62)
For i = 0 To 62
b(i) = 2 ^ i
Next
End If
If bit < 63 Then LongLongBitIsSet = theLongLong And b(bit)
End Function
'------------------------------------------------------------------
MsgBox LongBitIsSet(255, 7) '<--displays: True
MsgBox LongBitIsSet(230, 0) '<--displays: False
MsgBox LongBitIsSet(16384, 14) '<--displays: True
MsgBox LongBitIsSet(-16383, 0) '<--displays: True
MsgBox LongBitIsSet(&H7FFFFFFF, 0), 0) '<--displays: True
MsgBox LongLongBitIsSet(&H7FFFFFFFFFFFFFff^, 62) '<--displays: True
'
'
'