vba test if specific bits are set in 32-bit long integer code example

Example 1: excel vba are bits set in integer

'Fast VBA function to test if specific bits are set 
'within a 16-bit Integer. If ALL specified bits are set then 
'this function returns True. If ANY of the specified bits are
'not set then this function returns False.

'Bits are numbered from 0 to 15, so the first (least significant) bit
'is bit 0.

'Note: bits can be specified in any order.
'Note: any number of bits can be specified in one call.


Function IntegerBitsAreSet(theInteger%, ParamArray bits()) As Boolean
    Static i&, b%()
    If UBound(bits) = -1 Then Exit Function
    If (Not Not b) = 0 Then
        ReDim b(0 To 14)
        For i = 0 To 14
            b(i) = 2 ^ i
        Next
    End If
    For i = 0 To UBound(bits)
        If bits(i) < 0 Then Exit Function
        If bits(i) > 14 Then Exit Function
        If (theInteger And b(Int(bits(i)))) = 0 Then Exit Function
    Next
    IntegerBitsAreSet = True
End Function


'----------------------------------------------------------------------------------------
MsgBox IntegerBitsAreSet(255, 7)           '<--displays: True     255 = 00000000 11111111
MsgBox IntegerBitsAreSet(230, 0)           '<--displays: False    230 = 00000000 11100110
MsgBox IntegerBitsAreSet(85, 0, 2, 6, 4)   '<--displays: True      85 = 00000000 01010101
MsgBox IntegerBitsAreSet(85, 0, 2, 5, 4)   '<--displays: False     85 = 00000000 01010101
MsgBox IntegerBitsAreSet(485, 2, 7, 5)     '<--displays: True     485 = 00000001 11100101
MsgBox IntegerBitsAreSet(24585, 14, 13, 3) '<--displays: True   24585 = 01100000 00001001        
'
'
'

Example 2: excel vba are bits set in byte

'Fast VBA function to test if specific bits are set 
'within a Byte. If ALL specified bits are set then this function
'returns True. If ANY of the specified bits are not set then
'this function returns False.

'Bits are numbered from 0 to 7, so the first (least significant) bit
'is bit 0.

'Note: bits can be specified in any order.


Function ByteBitsAreSet(theByte As Byte, ParamArray bits()) As Boolean
    Static i&, b() As Byte
    If UBound(bits) = -1 Then Exit Function
    If (Not Not b) = 0 Then
        ReDim b(0 To 7)
        For i = 0 To 7
            b(i) = 2 ^ i
        Next
    End If
    For i = 0 To UBound(bits)
        If bits(i) < 0 Then Exit Function
        If bits(i) > 7 Then Exit Function
        If (theByte And b(Int(bits(i)))) = 0 Then Exit Function
    Next
    ByteBitsAreSet = True
End Function


'--------------------------------------------------------------------------
MsgBox ByteBitsAreSet(255, 7)           '<--displays: True   255 = 11111111
MsgBox ByteBitsAreSet(230, 0)           '<--displays: False  230 = 11100110
MsgBox ByteBitsAreSet(85, 0, 2, 6, 4)   '<--displays: True    85 = 01010101
MsgBox ByteBitsAreSet(85, 0, 2, 5, 4)   '<--displays: False   85 = 01010101
'
'
'

Example 3: excel vba is bit set long

'Extremely fast VBA function to test if a specified bit is set 
'within a 32-bit Long integer.

'Bits are numbered from 0 to 31, so the first (least significant) bit
'is bit 0.

'Note: we do not inspect bit 31, the sign bit.
'Note: any number of bits can be specified in one call.


Function LongBitIsSet(theLong&, bit As Byte) As Boolean
    Static i&, b&()
    If (Not Not b) = 0 Then
        ReDim b(0 To 30)
        For i = 0 To 30
            b(i) = 2 ^ i
        Next
    End If
    If bit < 31 Then LongBitIsSet = theLong And b(bit)
End Function


'------------------------------------------------------------------
MsgBox LongBitIsSet(255, 7)             '<--displays: True
MsgBox LongBitIsSet(230, 0)             '<--displays: False
MsgBox LongBitIsSet(16384, 14)          '<--displays: True
MsgBox LongBitIsSet(-16383, 0)          '<--displays: True
MsgBox LongBitIsSet(&H7FFFFFFF, 0)      '<--displays: True