Warning: mysqli_error() expects exactly 1 parameter, 0 given error

Change

die (mysqli_error()); 

to

die('Error: ' . mysqli_error($myConnection));

in the query

$query = mysqli_query($myConnection, $sqlCommand) or die (mysqli_error()); 

mysqli_error function requires $myConnection as parameters, that's why you get the warning

mysqli_error() needs you to pass the connection to the database as a parameter. Documentation here has some helpful examples:

http://php.net/manual/en/mysqli.error.php

Try altering your problem line like so and you should be in good shape:

$query = mysqli_query($myConnection, $sqlCommand) or die (mysqli_error($myConnection));