What does the compiler error "missing binary operator before token" mean?

If you are on Linux, make sure that you do not have a header named features.h inside your project files. I had one with this name, which resulted in:

/usr/include/x86_64-linux-gnu/bits/huge_val.h:25: error: function pointer expected

or

/usr/include/bits/huge_val.h:26:18: error: missing binary operator before token "("

That is because some system headers like huge_val.h use macros like __GNUC_PREREQ that are defined by /usr/include/features.h (learn more about this header in this SO question).

In my case I first saw this error when I started to use gcc's -I option which suddenly made gcc select my project include directory before the default system include directories.

You get this error sometimes if you have -fno-operator-names in your compiler flags. I suffered from the exact error while building json and this solved it.

This is not a compiler error, it is a preprocessor error. It occurs when the preprocessor encounters invalid syntax while trying to evaluate an expression in a #if or #elif directive.

One common cause is the sizeof operator in an #if directive:

For example:

  #define NBITS (sizeof(TYPE)*8)
  //later
  #if (NBITS>16)    //ERROR

This is an error because sizeof is evaluated by the compiler, not the preprocesor.

Type casts are also not valid preprocessor syntax:

  #define ALLBITS ((unsigned int) -1)
  //later
  #if (ALLBITS>0xFFFF)    //ERROR

The rules for what can be in a valid expression are here.

Note also that #if will evaluate an undefined macro as 0, unless it looks like it takes arguments, in which case you also get this error:

So if THIS is undefined:

#if THIS == 0  //valid, true

#if THIS > 0 //valid, false

#if THIS() == 0  //invalid. ERROR

Typos in your #if statement can also cause this message.