What is EOF in the C programming language?

You should change your parenthesis to

while((c = getchar()) != EOF)

Because the "=" operator has a lower precedence than the "!=" operator. Then you will get the expected results. Your expression is equal to

while (c = (getchar()!= EOF))

You are getting the two 1's as output, because you are making the comparison "c!=EOF". This will always become one for the character you entered and then the "\n" that follows by hitting return. Except for the last comparison where c really is EOF it will give you a 0.

EDIT about EOF: EOF is typically -1, but this is not guaranteed by the standard. The standard only defines about EOF in section 7.19.1:

EOF which expands to an integer constant expression, with type int and a negative value, that is returned by several functions to indicate end-of-file, that is, no more input from a stream;

It is reasonable to assume that EOF equals -1, but when using EOF you should not test against the specific value, but rather use the macro.

On Linux systems and OS X, the character to input to cause an EOF is Ctrl-D. For Windows, it's Ctrl-Z.

Depending on the operating system, this character will only work if it's the first character on a line, i.e. the first character after an Enter. Since console input is often line-oriented, the system may also not recognize the EOF character until after you've followed it up with an Enter.

And yes, if that character is recognized as an EOF, then your program will never see the actual character. Instead, a C program will get a -1 from getchar().