what is in the python standard library code example
Example 1: python standard library
Example 2: python standard library
>>> timedelta(hours=-5)
datetiSupported operations:
Operation
Result
t1 = t2 + t3
Sum of t2 and t3. Afterwards t1-t2 == t3 and t1-t3 == t2 are true. (1)
t1 = t2 - t3
Difference of t2 and t3. Afterwards t1 == t2 - t3 and t2 == t1 + t3 are true. (1)(6)
t1 = t2 * i or t1 = i * t2
Delta multiplied by an integer. Afterwards t1 // i == t2 is true, provided i != 0.
In general, t1 * i == t1 * (i-1) + t1 is true. (1)
t1 = t2 * f or t1 = f * t2
Delta multiplied by a float. The result is rounded to the nearest multiple of timedelta.resolution using round-half-to-even.
f = t2 / t3
Division (3) of overall duration t2 by interval unit t3. Returns a float object.
t1 = t2 / f or t1 = t2 / i
Delta divided by a float or an int. The result is rounded to the nearest multiple of timedelta.resolution using round-half-to-even.
t1 = t2 // i or t1 = t2 // t3
The floor is computed and the remainder (if any) is thrown away. In the second case, an integer is returned. (3)
t1 = t2 % t3
The remainder is computed as a timedelta object. (3)
q, r = divmod(t1, t2)
Computes the quotient and the remainder: q = t1 // t2 (3) and r = t1 % t2. q is an integer and r is a timedelta object.
+t1
Returns a timedelta object with the same value. (2)
-t1
equivalent to timedelta(-t1.days, -t1.seconds, -t1.microseconds), and to t1* -1. (1)(4)
abs(t)
equivalent to +t when t.days >= 0, and to -t when t.days < 0. (2)
str(t)
Returns a string in the form [D day[s], ][H]H:MM:SS[.UUUUUU], where D is negative for negative t. (5)
repr(t)
Returns a string representation of the timedelta object as a constructor call with canonical attribute values.me.timedelta(days=-1, seconds=68400)
>>> print(_)
-1 day, 19:00:00