What is the difference between the dot product and the scalar projection?

Projection

The component of a vector a that is in the same direction as of vector b (Hence projection is a vector) Length of the projection does not depend on the length(magnitude) of b. See the image below

Projection has two parts:

(i) The direction where you're projecting onto. That's the unit vector in direction of b, which is computed by dividing b by the length of b. That is $$\frac{b}{||b||}$$

(ii) The component of a in the direction of b. That is, the "shadow" or image of a when you project it onto b. This is computed by $$\frac{a⋅b}{||b||}$$ . because a⋅b=||a|| ||b|| cos(θ). Hence

||a||cos(θ)= $\frac{a⋅b}{||b||}$
and that gives you (as in the triangle figure), the length of a's projection on the direction of b

Putting it together, the projection of a onto b is a vector of length $$\frac{a⋅b}{||b||}$$

in the direction of $\frac{b}{||b||}$, i.e. $$\frac{a.b}{||b||} \frac{b}{||b||} $$

Dot Product

It's simply the projection of one vector onto the other multiplied by the magnitude of other vector. The dot product tells you what amount of one vector goes in the direction of another (Thus its a scalar ) and hence do not have any direction .

a.b= ||a|| ||b|| cos(θ). Alternatively if a=(x1,y1) and b=(x2,y2) (Position vectors) the dot product is x1.x2+y1.y2 .

The output of a dot product is a real number. The output of a projection is a vector. If you look at the formulas, the scalar projection does not depend on the length of the vector you are projecting onto.

According to Wikipeda, the scalar projection does not depend on the length of the vector being projected on. If you double the length of the second vector in the dot product, the dot product doubles.