What is the most time efficient way to remove unordered duplicates in a 2D array?
Since you want to find unordered duplicates the best way to go is by typecasting. Typecast them as set
. Since set only contains immutable elements. So, I made a set of tuples
.
Note: The best way to eliminate duplicates is by making a
set
of the given elements.
>>> set(map(tuple,map(sorted,x)))
{(-3, -2, 4, 5), (-5, 0, 4, 5)}
The best way is to not generate the duplicates in the first place.
The idea is to first create all possible combinations of values that appear multiple times, where each appears 0, 1, ... times. Then, we complete them with all possible combinations of the unique elements.
from itertools import combinations, product, chain
from collections import Counter
nums = [-5,5,4,-3,0,0,4,-2]
def combinations_without_duplicates(nums, k):
counts = Counter(nums)
multiples = {val: count for val, count in counts.items() if count >= 2 }
uniques = set(counts) - set(multiples)
possible_multiples = [[[val]*i for i in range(count+1)] for val, count in multiples.items()]
multiples_part = (list(chain(*x)) for x in product(*possible_multiples))
# omit the ones that are too long
multiples_part = (lst for lst in multiples_part if len(lst) <= k)
# Would be at this point:
# [[], [0], [0, 0], [4], [4, 0], [4, 0, 0], [4, 4], [4, 4, 0], [4, 4, 0, 0]]
for m_part in multiples_part:
missing = k - len(m_part)
for c in combinations(uniques, missing):
yield m_part + list(c)
list(combinations_without_duplicates(nums, 4))
Output:
[[-3, -5, 5, -2],
[0, -3, -5, 5],
[0, -3, -5, -2],
[0, -3, 5, -2],
[0, -5, 5, -2],
[0, 0, -3, -5],
[0, 0, -3, 5],
[0, 0, -3, -2],
[0, 0, -5, 5],
[0, 0, -5, -2],
[0, 0, 5, -2],
[4, -3, -5, 5],
[4, -3, -5, -2],
[4, -3, 5, -2],
[4, -5, 5, -2],
[4, 0, -3, -5],
[4, 0, -3, 5],
[4, 0, -3, -2],
[4, 0, -5, 5],
[4, 0, -5, -2],
[4, 0, 5, -2],
[4, 0, 0, -3],
[4, 0, 0, -5],
[4, 0, 0, 5],
[4, 0, 0, -2],
[4, 4, -3, -5],
[4, 4, -3, 5],
[4, 4, -3, -2],
[4, 4, -5, 5],
[4, 4, -5, -2],
[4, 4, 5, -2],
[4, 4, 0, -3],
[4, 4, 0, -5],
[4, 4, 0, 5],
[4, 4, 0, -2],
[4, 4, 0, 0]]