What is the pandas equivalent of dplyr summarize/aggregate by multiple functions?
It is very easy to transition your R code into python code without learning APIs of pandas using datar
:
>>> from datar import f
>>> from datar.tibble import tibble
>>> from datar.dplyr import group_by, summarize
>>> from datar.base import min, max
>>> data = tibble(
... col1=[1,1,1,1,1,2,2,2,2,2],
... col2=[1,2,3,4,5,6,7,8,9,0],
... col3=[-1,-2,-3,-4,-5,-6,-7,-8,-9,0]
... )
>>> data >> group_by(f.col1) >> summarize(col2_agg=max(f.col2), col3_agg=min(f.col3))
col1 col2_agg col3_agg
0 1 5 -5
1 2 9 -9
I am the author of the package. Feel free to submit issues if you have any questions.
The equivalent of
df %>% groupby(col1) %>% summarize(col2_agg=max(col2), col3_agg=min(col3))
is
df.groupby('col1').agg({'col2': 'max', 'col3': 'min'})
which returns
col2 col3
col1
1 5 -5
2 9 -9
The returning object is a pandas.DataFrame with an index called col1
and columns named col2
and col3
. By default, when you group your data pandas sets the grouping column(s) as index for efficient access and modification. However, if you don't want that, there are two alternatives to set col1
as a column.
Pass
as_index=False
:df.groupby('col1', as_index=False).agg({'col2': 'max', 'col3': 'min'})
Call
reset_index
:df.groupby('col1').agg({'col2': 'max', 'col3': 'min'}).reset_index()
both yield
col1 col2 col3
1 5 -5
2 9 -9
You can also pass multiple functions to groupby.agg
.
agg_df = df.groupby('col1').agg({'col2': ['max', 'min', 'std'],
'col3': ['size', 'std', 'mean', 'max']})
This also returns a DataFrame but now it has a MultiIndex for columns.
col2 col3
max min std size std mean max
col1
1 5 1 1.581139 5 1.581139 -3 -1
2 9 0 3.535534 5 3.535534 -6 0
MultiIndex is very handy for selection and grouping. Here are some examples:
agg_df['col2'] # select the second column
max min std
col1
1 5 1 1.581139
2 9 0 3.535534
agg_df[('col2', 'max')] # select the maximum of the second column
Out:
col1
1 5
2 9
Name: (col2, max), dtype: int64
agg_df.xs('max', axis=1, level=1) # select the maximum of all columns
Out:
col2 col3
col1
1 5 -1
2 9 0
Earlier (before version 0.20.0) it was possible to use dictionaries for renaming the columns in the agg
call. For example
df.groupby('col1')['col2'].agg({'max_col2': 'max'})
would return the maximum of the second column as max_col2
:
max_col2
col1
1 5
2 9
However, it was deprecated in favor of the rename method:
df.groupby('col1')['col2'].agg(['max']).rename(columns={'max': 'col2_max'})
col2_max
col1
1 5
2 9
It can get verbose for a DataFrame like agg_df
defined above. You can use a renaming function to flatten those levels in that case:
agg_df.columns = ['_'.join(col) for col in agg_df.columns]
col2_max col2_min col2_std col3_size col3_std col3_mean col3_max
col1
1 5 1 1.581139 5 1.581139 -3 -1
2 9 0 3.535534 5 3.535534 -6 0
For operations like groupby().summarize(newcolumn=max(col2 * col3))
, you can still use agg by first adding a new column with assign
.
df.assign(new_col=df.eval('col2 * col3')).groupby('col1').agg('max')
col2 col3 new_col
col1
1 5 -1 -1
2 9 0 0
This returns maximum for old and new columns but as always you can slice that.
df.assign(new_col=df.eval('col2 * col3')).groupby('col1')['new_col'].agg('max')
col1
1 -1
2 0
Name: new_col, dtype: int64
With groupby.apply
this would be shorter:
df.groupby('col1').apply(lambda x: (x.col2 * x.col3).max())
col1
1 -1
2 0
dtype: int64
However, groupby.apply
treats this as a custom function so it is not vectorized. Up to now, the functions we passed to agg
('min', 'max', 'min', 'size' etc.) are vectorized and these are aliases for those optimized functions. You can replace df.groupby('col1').agg('min')
with df.groupby('col1').agg(min)
, df.groupby('col1').agg(np.min)
or df.groupby('col1').min()
and they will all execute the same function. You will not see the same efficiency when you use custom functions.
Lastly, as of version 0.20, agg
can be used on DataFrames directly, without having to group first. See examples here.