Why do **2 and ² behave differently when using the cross meta-operator?
The X
metaoperator takes the two lists it's given a combines them using the operator you give it. If you don't give it an operator it uses ,
as the default.
So in this case :
say 1, 3, 5, 7, 9 X²
The X
metaoperator is looking for an infix operator. ²
isn't an infix operator it's postfix.
So X
applies ,
as the operator. But now ²
is being evaluated as a list and in this case it's "this the number 2" property kicks in.
Basically these are the same :
say 1, 3, 5, 7, 9 X²
say 1, 3, 5, 7, 9 X, 2
If you want to square all the items in a list you want to use a map
operator. As you did at the start.
Meanwhile on IRC
<Doc_Holliwood> m: ².WHAT.say <camelia> rakudo-moar ed8f5141f: OUTPUT: «(Int)» <Doc_Holliwood> m: say 2 - ² <camelia> rakudo-moar ed8f5141f: OUTPUT: «0» * abraxxa has quit (Ping timeout: 252 seconds) <Doc_Holliwood> where is the magic? <Doc_Holliwood> m: 2².say <camelia> rakudo-moar ed8f5141f: OUTPUT: «4» <jnthn> I don't think there's any magic at all, it's just falling out of the standard parsing rules <AlexDaniel> u: ²⅓ <unicodable6> AlexDaniel, U+00B2 SUPERSCRIPT TWO [No] (²) <unicodable6> AlexDaniel, U+2153 VULGAR FRACTION ONE THIRD [No] (⅓) <Doc_Holliwood> somewhere something must be actively distinguishing <AlexDaniel> so any No has a numeric value <jnthn> Well, the parser knows when it's looking for a term and when it's looking for a postfix <AlexDaniel> you can use these unicode characters (that are No) as numeric literals <AlexDaniel> and yeah, what jnthn said :) <jnthn> It can't be looking for a postfix if it didn't yet see a term <AlexDaniel> we had a few tickets about this, people find it very surprising, but the parser doesn't <Doc_Holliwood> so ² is sometimes an int and sometimes its a postfix depending on context? <tobs> by the same rule, it can distinguish between multiplication and whatever star <AlexDaniel> well, similarly, yes <AlexDaniel> m: say (* * *)(2, 8) <camelia> rakudo-moar ed8f5141f: OUTPUT: «16» <jnthn> Doc_Holliwood: I guess, though only in the same sense that "+" in +$x is the numify operator, but in $a + $b it's the infix addition operator. <tobs> m: say 2²⁰ <camelia> rakudo-moar ed8f5141f: OUTPUT: «1048576» <jnthn> In general, the parser is always quite clear about what category of thing it would like to see next. <AlexDaniel> m: 2 2 <camelia> rakudo-moar ed8f5141f: OUTPUT: «===SORRY!=== Error while compiling <tmp>Two terms in a rowat <tmp>:1------> 2⏏ 2 expecting any of: infix infix stopper statement end statement modifier statement modifier…» <AlexDaniel> m: * 2 <camelia> rakudo-moar ed8f5141f: OUTPUT: «===SORRY!=== Error while compiling <tmp>Two terms in a rowat <tmp>:1------> *⏏ 2 expecting any of: infix infix stopper statement end statement modifier statement modifier …» <AlexDaniel> m: × 2 <camelia> rakudo-moar ed8f5141f: OUTPUT: «===SORRY!=== Error while compiling <tmp>Preceding context expects a term, but found infix × instead.at > <tmp>:1------> ×⏏ 2» <AlexDaniel> the error messages make it quite transparent :) <Doc_Holliwood> I'm just trying to wrap my head around the latest SO question. but it makes sense to me now. if ² ist a postfix, but X requires an infix. so X² cant DWTHAM <Doc_Holliwood> in order for say 1, 3, 5, 7, 9 X² to be 1 , 25, etc you would need to change how X works *** <jnthn> m: say (1, 3, 5, 7, 9)>>² *** <camelia> rakudo-moar ed8f5141f: OUTPUT: «(1 9 25 49 81)» <jnthn> Just use something that expects a postfix op :)