Why doesn't Python hash function give the same values when run on Android implementation?

hash() is randomised by default each time you start a new instance of recent versions (Python3.3+) to prevent dictionary insertion DOS attacks

Prior to that, hash() was different for 32bit and 64bit builds anyway.

If you want something that does hash to the same thing every time, use one of the hashes in hashlib

>>> import hashlib
>>> hashlib.algorithms
('md5', 'sha1', 'sha224', 'sha256', 'sha384', 'sha512')

for old python (at least, my Python 2.7), it seems that

hash(<some type>) = id(<type>) / 16

and for CPython id() is the address in memory - http://docs.python.org/2/library/functions.html#id

>>> id(int) / hash(int)                                                     
16                                                                              
>>> id(int) % hash(int)                                                 
0                                                                               

so my guess is that the Android port has some strange convention for memory addresses?

anyway, given the above, hashes for types (and other built-ins i guess) will differ across installs because functions are at different addresses.

in contrast, hashes for values (what i think you mean by "non-internal objects") (before the random stuff was added) are calculated from their values and so likely repeatable.

PS but there's at least one more CPython wrinkle:

>>> for i in range(-1000,1000):
...     if hash(i) != i: print(i)
...
-1

there's an answer here somewhere explaining that one...