Write a program to find DFS traversal of a given graph in c code example
Example 1: DFS program in c
// DFS algorithm in C
#include
#include
struct node {
int vertex;
struct node* next;
};
struct node* createNode(int v);
struct Graph {
int numVertices;
int* visited;
// We need int** to store a two dimensional array.
// Similary, we need struct node** to store an array of Linked lists
struct node** adjLists;
};
// DFS algo
void DFS(struct Graph* graph, int vertex) {
struct node* adjList = graph->adjLists[vertex];
struct node* temp = adjList;
graph->visited[vertex] = 1;
printf("Visited %d \n", vertex);
while (temp != NULL) {
int connectedVertex = temp->vertex;
if (graph->visited[connectedVertex] == 0) {
DFS(graph, connectedVertex);
}
temp = temp->next;
}
}
// Create a node
struct node* createNode(int v) {
struct node* newNode = malloc(sizeof(struct node));
newNode->vertex = v;
newNode->next = NULL;
return newNode;
}
// Create graph
struct Graph* createGraph(int vertices) {
struct Graph* graph = malloc(sizeof(struct Graph));
graph->numVertices = vertices;
graph->adjLists = malloc(vertices * sizeof(struct node*));
graph->visited = malloc(vertices * sizeof(int));
int i;
for (i = 0; i < vertices; i++) {
graph->adjLists[i] = NULL;
graph->visited[i] = 0;
}
return graph;
}
// Add edge
void addEdge(struct Graph* graph, int src, int dest) {
// Add edge from src to dest
struct node* newNode = createNode(dest);
newNode->next = graph->adjLists[src];
graph->adjLists[src] = newNode;
// Add edge from dest to src
newNode = createNode(src);
newNode->next = graph->adjLists[dest];
graph->adjLists[dest] = newNode;
}
// Print the graph
void printGraph(struct Graph* graph) {
int v;
for (v = 0; v < graph->numVertices; v++) {
struct node* temp = graph->adjLists[v];
printf("\n Adjacency list of vertex %d\n ", v);
while (temp) {
printf("%d -> ", temp->vertex);
temp = temp->next;
}
printf("\n");
}
}
int main() {
struct Graph* graph = createGraph(4);
addEdge(graph, 0, 1);
addEdge(graph, 0, 2);
addEdge(graph, 1, 2);
addEdge(graph, 2, 3);
printGraph(graph);
DFS(graph, 2);
return 0;
} //code by Dungriyal
Example 2: dfs python
###############
#The Algorithm (In English):
# 1) Pick any node.
# 2) If it is unvisited, mark it as visited and recur on all its
# adjacent nodes.
# 3) Repeat until all the nodes are visited, or the node to be
# searched is found.
# The graph below (declared as a Python dictionary)
# is from the linked website and is used for the sake of
# testing the algorithm. Obviously, you will have your own
# graph to iterate through.
graph = {
'A' : ['B','C'],
'B' : ['D', 'E'],
'C' : ['F'],
'D' : [],
'E' : ['F'],
'F' : []
}
visited = set() # Set to keep track of visited nodes.
##################
# The Algorithm (In Code)
def dfs(visited, graph, node):
if node not in visited:
print (node)
visited.add(node)
for neighbour in graph[node]:
dfs(visited, graph, neighbour)
# Driver Code to test in python yourself.
# Note that when calling this, you need to
# call the starting node. In this case it is 'A'.
dfs(visited, graph, 'A')
# NOTE: There are a few ways to do DFS, depending on what your
# variables are and/or what you want returned. This specific
# example is the most fleshed-out, yet still understandable,
# explanation I could find.