Xamarin.Android Detect Emulator
using Xamarin.Essentials;
var isSimulator = DeviceInfo.DeviceType == DeviceType.Virtual;
It depends upon your goal of if this is just for local debug testing or if you plan to leave it in your code for testing within an end-user environment.
As the world of Android is quite large, this is an ever evolving method based upon what we seen in the wild:
public bool isEmulator(bool LicensedPlayers = false)
{
var detect = 0;
try
{
var teleManager = (TelephonyManager)GetSystemService(TelephonyService);
string networkOperator = "";
try
{
networkOperator = teleManager.NetworkOperator;
if (LicensedPlayers)
{
if ((teleManager.NetworkOperatorName == "T-Mobile") &&
(Build.Radio == "unknown") &&
(Build.Serial == "unknown") &&
(Build.Manufacturer == "samsung"))
{
D.WriteLine("BlueStacks (OS-X) Player");
detect += 1;
}
}
}
catch
{
networkOperator = "";
D.WriteLine("TelephonyService Exceptiion, custom emulator");
detect += 1;
}
if (networkOperator.Contains("Android"))
{
D.WriteLine("Google's Android Emulator");
detect += 1;
}
}
catch
{
D.WriteLine("TelephonyService not available, custom emulator");
detect += 1;
}
if (LicensedPlayers)
{
if (Build.Display.Contains("andy") || (Build.Hardware.Contains("andy")))
{
D.WriteLine("Andy Player");
detect += 1;
}
}
if (Build.Hardware.Contains("goldfish"))
{
D.WriteLine("Goldfish-based Emulator");
detect += 1;
}
if (Build.Display.ToLowerInvariant().Contains("xamarin"))
{
D.WriteLine("Xamarin Android Player");
detect += 1;
}
if (Build.Hardware.Contains("vsemu"))
{
D.WriteLine("Visual Studio Android Emulator");
detect += 1;
}
if (Build.Host.Contains("genymobile") || (Build.Manufacturer.ToLowerInvariant().Contains("genymotion")))
{
D.WriteLine("Genymotion Android Emulator");
detect += 1;
}
if (Build.Hardware.Contains("vbox") && Build.Hardware.Contains("86"))
{
D.WriteLine("VirtualBox-based Emulator");
detect += 1;
}
return detect > 0;
}
Updated: Fixed XAP emulator detection on multiple platforms