Xsd and inheritance
Simply add an <xsd:sequence>
with the required elements:
<xsd:complexType name="B">
<xsd:complexContent>
<xsd:extension base="A">
<xsd:sequence>
<xsd:element name="Hours">
...
</xsd:element>
</xsd:sequence>
</xsd:extension>
</xsd:complexContent>
</xsd:complexType>
You will need to define options as a complex type of it's own, then use extension on that to create a new options complex type and use substitution instead of extension.
Here's the schema I came up with:
<?xml version="1.0" encoding="utf-8"?>
<xs:schema id="inheritance"
targetNamespace="http://test.com"
elementFormDefault="qualified"
xmlns="http://www.w3.org/2001/XMLSchema"
xmlns:test="http://test.com"
>
<xs:element name="Time">
<xs:complexType>
<xs:sequence>
<xs:element name="First" type="test:A" />
<xs:element name="Second" type="test:B" />
</xs:sequence>
</xs:complexType>
</xs:element>
<xs:complexType name="shortOptions">
<xs:sequence>
<xs:element name="Day" />
</xs:sequence>
</xs:complexType>
<xs:complexType name="longOptions">
<xs:complexContent>
<xs:extension base="test:shortOptions">
<xs:sequence>
<xs:element name="Week" />
</xs:sequence>
</xs:extension>
</xs:complexContent>
</xs:complexType>
<xs:complexType name="A">
<xs:sequence>
<xs:element name="options" type="test:shortOptions" />
</xs:sequence>
</xs:complexType>
<xs:complexType name="B">
<xs:sequence>
<xs:element name="options" type="test:longOptions" />
</xs:sequence>
</xs:complexType>
</xs:schema>
Which seems to fit this xml:
<?xml version="1.0" encoding="utf-8" ?>
<Time xmlns="http://test.com">
<First>
<options>
<Day>Today</Day>
</options>
</First>
<Second>
<options>
<Day>Tomorrow</Day>
<Week>This Week</Week>
</options>
</Second>
</Time>