Adding Convenience Initializers in Swift Subclass

Building on Matt's answer, we had to include an additional function, or else the compiler complained about invoking an initializer with no arguments.

Here's what worked to subclass SKShapeNode:

class CircleNode : SKShapeNode {

    override init() {
        super.init()
    }

    convenience init(width: CGFloat, point: CGPoint) {
        self.init()
        self.init(circleOfRadius: width/2)
        // Do stuff
     }

    required init?(coder aDecoder: NSCoder) {
        fatalError("init(coder:) has not been implemented")
    }
}

My understanding of Initializer Inheritance is the same as yours, and I think we are both well aligned with what the book states. I don't think it's an interpretation issue or a misunderstanding of the stated rules. That said, I don't think you're doing anything wrong.

I tested the following in a Playground and it works as expected:

class RectShape: NSObject {
    var size = CGSize(width: 0, height: 0)
    convenience init(rectOfSize size: CGSize) {
        self.init()
        self.size = size
    }
}

class SquareShape: RectShape {
    convenience init(squareOfSize size: CGFloat) {
        self.init(rectOfSize: CGSize(width: size, height: size))
    }
}

RectShape inherits from NSObject and doesn't define any designated initializers. Thus, as per Rule 1, it inherits all of NSObject's designated initializers. The convenience initializer I provided in the implementation correctly delegates to a designated initializer, prior to doing the setup for the intance.

SquareShape inherits from RectShape, doesn't provide a designated initializer and, again, as per Rule 1, inherits all of SquareShape's designated initializers. As per Rule 2, it also inherits the convenience initializer defined in RectShape. Finally, the convenience initializer defined in SquareShape properly delegates across to the inherited convenience initializer, which in turn delegates to the inherited designated initializer.

So, given the fact you're doing nothing wrong and that my example works as expected, I am extrapolating the following hypothesis:

Since SKShapeNode is written in Objective-C, the rule which states that "every convenience initializer must call another initializer from the same class" is not enforced by the language. So, maybe the convenience initializer for SKShapeNode doesn't actually call a designated initializer. Hence, even though the subclass MyShapeNode inherits the convenience initializers as expected, they don't properly delegate to the inherited designated initializer.

But, again, it's only a hypothesis. All I can confirm is that the mechanics works as expected on the two classes I created myself.

There are two problems here:

• SKShapeNode has only one designated initializer: init(). This means that we cannot get out of our initializer without calling init().

• SKShapeNode has a property path declared as CGPath!. This means that we don't want to get out of our initializer without somehow initializing the path.

The combination of those two things is the source of the issue. In a nutshell, SKShapeNode is incorrectly written. It has a property path that must be initialized; therefore it should have a designated initializer that sets the path. But it doesn't (all of its path-setting initializers are convenience initializers). That's the bug. Putting it another way, the source of the problem is that, convenience or not, the shapeNodeWith... methods are not really initializers at all.

You can, nevertheless, do what you want to do — write a convenience initializer without being forced to write any other initializers — by satisfying both requirements in that order, i.e. by writing it like this:

class MyShapeNode : SKShapeNode {
    convenience init(squareOfSize value: CGFloat) {
        self.init()
        self.init(rectOfSize: CGSizeMake(value, value))
    }
}

It looks illegal, but it isn't. Once we've called self.init(), we've satisfied the first requirement, and we are now free to refer to self (we no longer get the "use of 'self' in delegating initializer before self.init is called" error) and satisfy the second requirement.