Android difference between two dates in seconds

You can turn a date object into a long (milliseconds since Jan 1, 1970), and then use TimeUnit to get the number of seconds:

long diffInMs = endDate.getTime() - startDate.getTime();

long diffInSec = TimeUnit.MILLISECONDS.toSeconds(diffInMs);

Edit: -Corrected the name of the variable diffInMs which was written diffInM(i)s in the second line.

try below method:-

    public String twoDatesBetweenTime(String oldtime)
    {
        // TODO Auto-generated method stub
        int day = 0;
        int hh = 0;
        int mm = 0;
        try
        {
            SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
            Date oldDate = dateFormat.parse(oldtime);
            Date cDate = new Date();
            Long timeDiff = cDate.getTime() - oldDate.getTime();
            day = (int) TimeUnit.MILLISECONDS.toDays(timeDiff);
            hh = (int) (TimeUnit.MILLISECONDS.toHours(timeDiff) - TimeUnit.DAYS.toHours(day));
            mm = (int) (TimeUnit.MILLISECONDS.toMinutes(timeDiff) - TimeUnit.HOURS.toMinutes(TimeUnit.MILLISECONDS.toHours(timeDiff)));
        }
        catch (ParseException e)
        {
            e.printStackTrace();
        }
        if(day==0)
        {
            return hh + " hour " + mm + " min";
        }
        else if(hh==0)
        {
            return mm + " min";
        }
        else
        {
            return day + " days " + hh + " hour " + mm + " min";
        }
    }