BASH - How to extract data from a column in CSV file and put it in an array?

Remove the IFS="," assignment thereby letting the default IFS value of space, tab, newline apply

#!/bin/bash

eCollection=( $(cut -d ',' -f2 MyAssignment.csv ) )
printf "%s\n" "${eCollection[0]}"

Explained: The eCollection variable is an array due to the outer parenthesis. It is initialized with each element from the IFS-separated (think function or command line arguments) words which come from the $(cut -d ',' -f2 MyAssignment.csv) subshell, which is the cut command used with the ',' delimiter and printing the second field -f2 from the MyAssignment.csv file.

The printf statement just shows how to print any item by index, you could also try echo "${eCollection[@}]}" to see all of the elements.

Two pure bash solutions:

eCollection=()
while IFS=',' read -r _ second _; do
    eCollection+=("$second")
done < file.txt
printf '%s\n' "${eCollection[0]}"

readarray -t eCollection < file.txt
eCollection=("${eCollection[@]#*,}")
eCollection=("${eCollection[@]%%,*}")
printf '%s\n' "${eCollection[0]}"

Better is to use readarray. No need to mind about IFS which could have any value, and is safe from pathname expansion.

readarray -t eCollection < <(cut -d, -f2 MyAssignment.csv)
printf '%s\n' "${eCollection[0]}"