C Function to Convert float to byte array

Easiest is to make a union:

#include <stdio.h>

int main(void) {
  int ii;
  union {
    float a;
    unsigned char bytes[4];
  } thing;

  thing.a = 1.234;
  for (ii=0; ii<4; ii++) 
    printf ("byte %d is %02x\n", ii, thing.bytes[ii]);
  return 0;
}

Output:

byte 0 is b6
byte 1 is f3
byte 2 is 9d
byte 3 is 3f

Note - there is no guarantee about the byte order… it depends on your machine architecture.

To get your function to work, do this:

void float2Bytes(byte bytes_temp[4],float float_variable){ 
  union {
    float a;
    unsigned char bytes[4];
  } thing;
  thing.a = float_variable;
  memcpy(bytes_temp, thing.bytes, 4);
}

Or to really hack it:

void float2Bytes(byte bytes_temp[4],float float_variable){ 
  memcpy(bytes_temp, (unsigned char*) (&float_variable), 4);
}

Note - in either case I make sure to copy the data to the location given as the input parameter. This is crucial, as local variables will not exist after you return (although you could declare them static, but let's not teach you bad habits. What if the function gets called again…)

Here's a way to do what you want that won't break if you're on a system with a different endianness from the one you're on now:

byte* floatToByteArray(float f) {
    byte* ret = malloc(4 * sizeof(byte));
    unsigned int asInt = *((int*)&f);

    int i;
    for (i = 0; i < 4; i++) {
        ret[i] = (asInt >> 8 * i) & 0xFF;
    }

    return ret;
}

You can see it in action here: http://ideone.com/umY1bB

The issue with the above answers is that they rely on the underlying representation of floats: C makes no guarantee that the most significant byte will be "first" in memory. The standard allows the underlying system to implement floats however it feels like -- so if you test your code on a system with a particular kind of endianness (byte order for numeric types in memory), it will stop working depending on the kind of processor you're running it on.

That's a really nasty, hard-to-fix bug and you should avoid it if at all possible.

Yet another way, without unions: (Assuming byte = unsigned char)

void floatToByte(byte* bytes, float f){

  int length = sizeof(float);

  for(int i = 0; i < length; i++){
    bytes[i] = ((byte*)&f)[i];
  }

}

I would recommend trying a "union".

Look at this post:

http://forum.arduino.cc/index.php?topic=158911.0

typedef union I2C_Packet_t{
 sensorData_t sensor;
 byte I2CPacket[sizeof(sensorData_t)];
};

In your case, something like:

union {
  float float_variable;
  char bytes_array[4];
} my_union;

my_union.float_variable = 1.11;