Command to remove all npm modules globally?
The following command removes all global npm modules. Note: this does not work on Windows. For a working Windows version, see Ollie Bennett's Answer.
npm ls -gp --depth=0 | awk -F/ '/node_modules/ && !/\/npm$/ {print $NF}' | xargs npm -g rm
Here is how it works:
npm ls -gp --depth=0
lists all global top level modules (see the cli documentation for ls)awk -F/ '/node_modules/ && !/\/npm$/ {print $NF}'
prints all modules that are not actually npm itself (does not end with/npm
)xargs npm -g rm
removes all modules globally that come over the previous pipe
sudo npm list -g --depth=0. | awk -F ' ' '{print $2}' | awk -F '@' '{print $1}' | sudo xargs npm remove -g
worked for me
sudo npm list -g --depth=0.
lists all top level installedawk -F ' ' '{print $2}'
gets rid of ├──awk -F '@' '{print $1}'
gets the part before '@'sudo xargs npm remove -g
removes the package globally
I tried Kai Sternad's solution but it seemed imperfect to me. There was a lot of special symbols left after the last awk
from the deps tree itself.
So, I came up with my own modification of Kai Sternad's solution (with a little help from cashmere's idea):
npm ls -gp --depth=0 | awk -F/node_modules/ '{print $2}' | grep -vE '^(npm|)$' | xargs -r npm -g rm
npm ls -gp --depth=0
lists all globally-installed npm modules in parsable format:
/home/leonid/local/lib
/home/leonid/local/lib/node_modules/bower
/home/leonid/local/lib/node_modules/coffee-script
...
awk -F/node_modules/ '{print $2}'
extracts module names from paths, forming the list of all globally-installed modules.
grep -vE '^(npm|)$'
removes npm itself and blank lines.
xargs -r npm -g rm
calls npm -g rm
for each module in the list.
Like Kai Sternad's solution, it'll only work under *nix.
For those using Windows, the easiest way to remove all globally installed npm packages is to delete the contents of:
C:\Users\username\AppData\Roaming\npm
You can get there quickly by typing %appdata%/npm
in either the explorer, run prompt, or from the start menu.