Compare if BigDecimal is greater than zero

Use compareTo() function that's built into the class.

it is safer to use the method compareTo()

    BigDecimal a = new BigDecimal(10);
    BigDecimal b = BigDecimal.ZERO;

    System.out.println(" result ==> " + a.compareTo(b));

console print

    result ==> 1

compareTo() returns

• 1 if a is greater than b
• -1 if a is less than b
• 0 if a is equal to b

now for your problem you can use

if (value.compareTo(BigDecimal.ZERO) > 0)

or

if (value.compareTo(new BigDecimal(0)) > 0)

I hope it helped you.

Possible better way:

if (value.signum() > 0)

signum returns -1, 0, or 1 as the value of this BigDecimal is negative, zero, or positive.

It's as simple as:

if (value.compareTo(BigDecimal.ZERO) > 0)

The documentation for compareTo actually specifies that it will return -1, 0 or 1, but the more general Comparable<T>.compareTo method only guarantees less than zero, zero, or greater than zero for the appropriate three cases - so I typically just stick to that comparison.