Convert hexadecimal string (hex) to a binary string
Fast, and works for large strings:
private String hexToBin(String hex){
hex = hex.replaceAll("0", "0000");
hex = hex.replaceAll("1", "0001");
hex = hex.replaceAll("2", "0010");
hex = hex.replaceAll("3", "0011");
hex = hex.replaceAll("4", "0100");
hex = hex.replaceAll("5", "0101");
hex = hex.replaceAll("6", "0110");
hex = hex.replaceAll("7", "0111");
hex = hex.replaceAll("8", "1000");
hex = hex.replaceAll("9", "1001");
hex = hex.replaceAll("A", "1010");
hex = hex.replaceAll("B", "1011");
hex = hex.replaceAll("C", "1100");
hex = hex.replaceAll("D", "1101");
hex = hex.replaceAll("E", "1110");
hex = hex.replaceAll("F", "1111");
return hex;
}
BigInteger.toString(radix)
will do what you want. Just pass in a radix of 2.
static String hexToBin(String s) {
return new BigInteger(s, 16).toString(2);
}
Integer.parseInt(hex,16);
System.out.print(Integer.toBinaryString(hex));
Parse hex(String) to integer with base 16 then convert it to Binary String using toBinaryString(int) method
example
int num = (Integer.parseInt("A2B", 16));
System.out.print(Integer.toBinaryString(num));
Will Print
101000101011
Max Hex vakue Handled by int is FFFFFFF
i.e. if FFFFFFF0 is passed ti will give error