Curly braces in math mode
Use \{…\}
. But, as the contents inside the braces may vary in size, it would be better to use the DeclarePairedDelimiter
command from the mathtools
package:
\DeclarePairedDelimiter\set\{\}
This defines a \set{…}
command, which accepts an optional argument: \big
, \Big
, \bigg
, or \Bigg
, which implicitly adds a pair of \bigl…\bigr
, &c. in front of the braces. Example: \set[\big]{...}
A \set*{…}
variant becomes available for free, which adds implicitly a pair of \left…\right
.
You need to escape the braces like \{
and \}
.
$K_1 = \{s_1\}, K_2 = \{s_2, s_3, s_4\}$
Also possible to use dynamic delimiter sizing with \left
and right
, example below.
Calculate the first 4 terms of the sequence below, here typeset
without dynamic delimiter sizing:
\begin{equation}
\{ a_n \} = \{ -(\frac{1}{n})^n \}
\end{equation}
With dynamic delimiter sizing of the curly braces using `\left` and
`\right` the sequence looks like
\begin{equation}
\{ a_n \} = \left\{ -(\frac{1}{n})^n \right\}
\end{equation}
Off course we can also apply this to the parenthesis
\begin{equation}
\{ a_n \} = \left\{ - \left( \frac{1}{n} \right)^n \right\}
\end{equation}
Finally, the answer to the question is $\{ -1,1/4,-1/27,1/256,... \}$