Decimal to Hexadecimal Converter in Java

Consider dec2m method below for conversion from dec to hex, oct or bin.

Sample output is

28 dec == 11100 bin 28 dec == 34 oct 28 dec == 1C hex

public class Conversion {
    public static void main(String[] argv) {
        int x = 28;                           // sample number
        if (argv.length > 0)
            x = Integer.parseInt(argv[0]);    // number from command line

        System.out.printf("%d dec == %s bin\n", i, dec2m(x, 2));
        System.out.printf("%d dec == %s oct\n", i, dec2m(x, 8));
        System.out.printf("%d dec == %s hex\n", i, dec2m(x, 16));
    }

    static String dec2m(int N, int m) {
        String s = "";
        for (int n = N; n > 0; n /= m) {
            int r = n % m;
            s = r < 10 ? r + s : (char) ('A' - 10 + r) + s;
        }
        return s;
    }
}

Simple:

  public static String decToHex(int dec)
  {
        return Integer.toHexString(dec);
  }

As mentioned here: Java Convert integer to hex integer

One possible solution:

import java.lang.StringBuilder;

class Test {
  private static final int sizeOfIntInHalfBytes = 8;
  private static final int numberOfBitsInAHalfByte = 4;
  private static final int halfByte = 0x0F;
  private static final char[] hexDigits = { 
    '0', '1', '2', '3', '4', '5', '6', '7', 
    '8', '9', 'A', 'B', 'C', 'D', 'E', 'F'
  };

  public static String decToHex(int dec) {
    StringBuilder hexBuilder = new StringBuilder(sizeOfIntInHalfBytes);
    hexBuilder.setLength(sizeOfIntInHalfBytes);
    for (int i = sizeOfIntInHalfBytes - 1; i >= 0; --i)
    {
      int j = dec & halfByte;
      hexBuilder.setCharAt(i, hexDigits[j]);
      dec >>= numberOfBitsInAHalfByte;
    }
    return hexBuilder.toString(); 
  }

  public static void main(String[] args) {
     int dec = 305445566;
     String hex = decToHex(dec);
     System.out.println(hex);       
  }
}

Output:

1234BABE

Anyway, there is a library method for this:

String hex = Integer.toHexString(dec);

I need a function that takes in an int dec and returns a String hex.

I found a more elegant solution from http://introcs.cs.princeton.edu/java/31datatype/Hex2Decimal.java.html . I changed a bit from the original ( see the edit )

// precondition:  d is a nonnegative integer
public static String decimal2hex(int d) {
    String digits = "0123456789ABCDEF";
    if (d <= 0) return "0";
    int base = 16;   // flexible to change in any base under 16
    String hex = "";
    while (d > 0) {
        int digit = d % base;              // rightmost digit
        hex = digits.charAt(digit) + hex;  // string concatenation
        d = d / base;
    }
    return hex;
}

Disclaimer: I ask this question in my coding interview. I hope this solution doesn't get too popular :)

Edit June 17 2016 : I added the base variable to give the flexibility to change into any base : binary, octal, base of 7 ...
According to the comments, this solution is the most elegant so I removed the implementation of Integer.toHexString() .

Edit September 4 2015 : I found a more elegant solution http://introcs.cs.princeton.edu/java/31datatype/Hex2Decimal.java.html