Don't navigate to other pages in WebView,disable links and references

You should save in a class variable your current url and check if it's the same with the loaded one. When the user clicks on a link the shouldOverrideUrlLoading is called and check the website. Something like this:

private String currentUrl;

public ourWebViewClient(String currentUrl) {
    this.currentUrl = currentUrl;
}

@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
    if (url.equals(currentUrl)) {
        view.loadUrl(url);  
    }
    return true;
}

Important: don't forget set the WebViewClient to your WebView.

ourWebViewClient webViewClient = new ourWebViewClient(urlToLoad);
wv.setWebViewClient(webViewClient);

Implement a WebViewClient and Just return true from this method of WebView Client

webView.setWebViewClient(new WebViewClient(){
    public boolean shouldOverrideUrlLoading(WebView view, String url) {
        return true;
    }
});

If you want to open inner link of a web page in different window then

Don't use

WebView webView;//Your WebView Object
webView.setWebViewClient(new HelpClient());// Comment this line

B'coz setWebViewClient() method is taking care of opening a new page in the same webview. So simple comment this line.

private class HelpClient extends WebViewClient {
    @Override
    public boolean shouldOverrideUrlLoading(WebView view, String url) {
        if (Uri.parse(url).getHost().equals("www.example.com")) {
            // This is my web site, so do not override; let my WebView load the page
            return false;
        }
        // Otherwise, the link is not for a page on my site, so launch another Activity that handles URLs
        Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(url));
        startActivity(intent);
        return true;
    }
}

Hope this will work.