Fill cells with colors using openpyxl?

in python 3.x

wb = openpyxl.Workbook()
ws = wb.active
redFill = PatternFill(start_color='FFFF0000',
                   end_color='FFFF0000',
                   fill_type='solid')
ws['A1'].fill = redFill

that working but i dont know in python 2.x i hope working just put ws['A1'].fill=redFill

This worked for me. They changed things and most of the help you see on the internet is for older versions of the openpyxl library from what I am seeing.

# Change background color 
xls_cell.style = Style(fill=PatternFill(patternType='solid',
                                        fill_type='solid', 
                                        fgColor=Color('C4C4C4')))

I believe the issue is that you're trying to assign a fill object to a style.

ws['A1'].fill = redFill should work fine.

The API for styles changed once again. What worked for me was

my_red = openpyxl.styles.colors.Color(rgb='00FF0000')
my_fill = openpyxl.styles.fills.PatternFill(patternType='solid', fgColor=my_red)
cell.fill = my_fill

Color is an alpha RGB hex color. You can pass it in as 'rrggbb' with a default alpha of 00 or specify the alpha with 'aarrggbb'. A bunch of colors are defined as constants in openpyxl.styles.colors if you need to grab one quickly.