Filling between parametric plots

ParametricPlot

Here's a way that seems to work in your case (see below in @ssch's (thanks!) comments when it doesn't)

Let (for better readability)

f1[u_] := {u + Sin[u], -Cos[u]}
f2[u_] := {u + Sin[u + Pi], Cos[u + Pi]}

And then

ParametricPlot[{ v f1[u] + (1 - v) f2[u]}, {u, 0, Pi}, {v, 0, 1}, 
   Axes -> True, Mesh -> None, PlotStyle -> LightGray]

i.e., we just add an auxiliary parameter v, to "shift" between the curves.

enter image description here

Using ColorFunction, you can add more colors:

ParametricPlot[{v f1[u] + (1 - v) f2[u]}, {u, 0, Pi}, {v, 0, 1}, 
  Axes -> True, Mesh -> None, ColorFunction -> Function[{x, y, u, v}, Hue[v]]]

(I won't paste a picture of that here)


ListLinePlot

For ListLinePlot, note that your data is wrongly formatted, try e.g.:

ListLinePlot[
   Transpose@Table[{{u + Sin[u], -Cos[u]}, {u + Sin[u + Pi], Cos[u + Pi]}}, 
      {u, 0, Pi, 0.01}], Filling -> {1 -> {2}}]

Note the Transpose I added to fix the issue.


Similar to @ybeltukov, you can extract the lines from the plot. But to get a proper polygon, you need to reverse one of the lines.

plot = ParametricPlot[{{u + Sin[u], -Cos[u]}, {u + Sin[u + Pi], 
     Cos[u + Pi]}}, {u, 0, Pi}, Axes -> True];
{line1, line2} = Cases[plot, l_Line :> First@l, Infinity];

Graphics[
 {Opacity[0.4], Darker@Blue, EdgeForm[Darker@Blue], 
  Polygon[Join[line1, Reverse@line2]]},
 Options[plot]
 ]

Mathematica graphics

Then one can style the polygon and/or lines as desired.

Graphics[
 {{Opacity[0.4], ColorData[1][3], 
   Polygon[Join[line1, Reverse@line2]]}, Thick, ColorData[1][1], 
  Line@line1, ColorData[1][2], Line@line2},
 Options[plot]
 ]

Mathematica graphics


A subtly different ListLinePlot approach:

ListLinePlot[{
      Table[{u + Sin[u], -Cos[u]}, {u, 0, Pi, 0.005}],
      Table[{u + Sin[u + Pi], Cos[u + Pi]}, {u, 0, Pi, 0.005}]},
          Filling -> {1 -> {{2}, LightGray}}, PlotStyle -> Black]

It looks better to me in terms of jaggies:

enter image description here