Get parents keys from nested dictionary
recursion to the rescue!
example_dict = { 'key1' : 'value1',
'key2' : 'value2',
'key3' : { 'key3a': 'value3a' },
'key4' : { 'key4a': { 'key4aa': 'value4aa',
'key4ab': 'value4ab',
'key4ac': 'value4ac'},
'key4b': 'value4b'}
}
def find_key(d, value):
for k,v in d.items():
if isinstance(v, dict):
p = find_key(v, value)
if p:
return [k] + p
elif v == value:
return [k]
print find_key(example_dict,'value4ac')
how it works
It looks through the items and checks 2 cases
- item isn't a dictionary -- In this case, see if it is the value we're looking for. If it is, return a list which contains only the key. (This is our base-case for recursion).
- item is a dictionary -- Try looking for the key in that dictionary. If it is found in that dictionary (or any sub-dict), return the key which takes the right path pre-pended onto the rest of the path.
What if your dictionary contains lists too?
Here's a more broad variant of @mgilson 's solution, suitable for JSON:
example_dict_with_list = { 'key1' : 'value1',
'key2' : 'value2',
'key3' : { 'key3a': 'value3a' },
'key4' : { 'key4a': [{ 'key4aa': 'value4aa',
'key4ab': 'value4ab',
'key4ac': 'value4ac'}],
'key4b': 'value4b'}
}
def breadcrumb(json_dict_or_list, value):
if json_dict_or_list == value:
return [json_dict_or_list]
elif isinstance(json_dict_or_list, dict):
for k, v in json_dict_or_list.items():
p = breadcrumb(v, value)
if p:
return [k] + p
elif isinstance(json_dict_or_list, list):
lst = json_dict_or_list
for i in range(len(lst)):
p = breadcrumb(lst[i], value)
if p:
return [str(i)] + p
print(
breadcrumb(example_dict_with_list, 'value4aa')
)
Which returns
['key4', 'key4a', '0', 'key4aa', 'value4aa']
Bonus
If you need to print it out nicely, like a string of breadcrums, do
print(
' > '.join(
breadcrumb(example_dict, 'value4aa')
)
)
Which will return
'key4 > key4a > 0 > key4aa > value4aa'