Getting element's name in XPATH

Use name(). (Find docs for newer versions of the XPath language here.)

Here are modified versions of your example:

Works in XPath 2.0 only:

//element/*[@id='elid']/name()

Works in XPath 1.0 and 2.0:

name(//element/*[@id='elid'])

You could also use local-name() which returns the local part of the expanded name (without any namespace prefix).

The tag names tree can also be obtained with

echo "du //Element/*" | xmllint --shell response-02.xml
Ele1
    id
    name
    Nested1
        id
        name
Ele2

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