Given a number, print out its "collective sum"
05AB1E, 4 3 bytes
-1 thanks to Kevin Cruijssen (use of €
avoiding a }
)
€£O
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How?
€£O - implicit input e.g. 2315
€ - map with:
£ - head to 23, 231, 2, 2315
O - sum 2571
Python 2, 43 bytes
lambda n:sum(int('0'+n[:int(x)])for x in n)
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Python 2, 72 bytes
First submission! Thanks to @DestructibleLemon for the help!
import sys;d=sys.argv[1];s=0;for e in d:s+=int(d[:int(e)]);print str(s)