Golang Invalid Receiver Type in Method Func
This is the best I can come up with:
type Connection ssh.Client
func (conn *Connection) SendCommand() ([]byte, error) {
(*ssh.Client)(conn).NewSession()
Note that I've changed the type to not be a pointer type (but then I've made a pointer receiver for SendCommand
). I'm not sure there's any way to create a function with a pointer type as a receiver.
Another option is to use type aliasing to achieve the desired behavior. I was trying to do something "clever" for readability:
type foo struct {
i int
}
type foo_ptr = *foo
type foo_ptr_slice = []foo_ptr
type foo_ptr_map = map[string]foo_ptr
type foo_ptr_slice_map = map[string]foo_ptr_slice
func (r foo_ptr) dump() {
fmt.Printf("%d\n", r.i)
}
func main() {
// need a map of slice of pointers
var m foo_ptr_map
m = make(foo_ptr_map, 0)
m["test"] = &foo{i: 1}
var m2 foo_ptr_slice_map
m2 = make(foo_ptr_slice_map, 0)
m2["test"] = make(foo_ptr_slice, 0, 10)
m2["test"] = append(m2["test"], &foo{i: 2})
fmt.Printf("%d\n", m["test"].i)
fmt.Printf("%d\n", m2["test"][0].i)
m["test"].dump()
}
I acknowledge that type aliasing is used for large-scale refactoring but this seems like a very good use for readability sake.
You can't declare a new type with a pointer TypeSpec. Also declaring a new type is used specifically to remove the entire method set, so you won't have any of the original methods from the *ssh.Client
.
What you want is to use composition by embedding the *ssh.Client
in your own struct type:
type Connection struct {
*ssh.Client
}
func Connect(addr, user, password string) (*Connection, error) {
sshConfig := &ssh.ClientConfig{
User: user,
Auth: []ssh.AuthMethod{
ssh.Password(password),
},
HostKeyCallback: ssh.HostKeyCallback(func(hostname string, remote net.Addr, key ssh.PublicKey) error { return nil }),
}
conn, err = ssh.Dial("tcp", addr, sshConfig)
if err != nil {
return nil, err
}
return &Connection{conn}, nil
}
func (conn *Connection) SendCommand() ([]byte, error) {
session, err := conn.NewSession()
// ...
}