How can I make gdb print unprintable characters of a string in hex instead of octal while preserving the ascii characters in ascii form?
You might use the x
command to dump the memory your char
-pointer points to:
(gdb) x/32xb buf
shows the first 32 bytes.
See
(gdb) help x
for details.
In the absence of an existing solution, I created this gdb command which prints ascii and hex for strings that have mixed printable ascii and non-printable characters. The source is reproduced below.
from __future__ import print_function
import gdb
import string
class PrettyPrintString (gdb.Command):
"Command to print strings with a mix of ascii and hex."
def __init__(self):
super (PrettyPrintString, self).__init__("ascii-print",
gdb.COMMAND_DATA,
gdb.COMPLETE_EXPRESSION, True)
gdb.execute("alias -a pp = ascii-print", True)
def invoke(self, arg, from_tty):
arg = arg.strip()
if arg == "":
print("Argument required (starting display address).")
return
startingAddress = gdb.parse_and_eval(arg)
p = 0
print('"', end='')
while startingAddress[p] != ord("\0"):
charCode = int(startingAddress[p].cast(gdb.lookup_type("char")))
if chr(charCode) in string.printable:
print("%c" % chr(charCode), end='')
else:
print("\\x%x" % charCode, end='')
p += 1
print('"')
PrettyPrintString()
To use this, one can simply put the source AsciiPrintCommand.py
and then run the following in gdb. For convenience, one can put put the above source command into their $HOME/.gdbinit
.
ascii-print buf
"Hello World \x1c"
For anyone else who shares the irritation with octal escape-sequences in GDB, it's easy to fix (if you're prepared to build GDB yourself): in gdb/valprint.c, find the comment:
/* If the value fits in 3 octal digits, print it that
way. Otherwise, print it as a hex escape. */
and comment out the following 4 lines - all escape-sequences will then be printed as hex.