How can I read an input string of unknown length?

Enter while securing an area dynamically

E.G.

#include <stdio.h>
#include <stdlib.h>

char *inputString(FILE* fp, size_t size){
//The size is extended by the input with the value of the provisional
    char *str;
    int ch;
    size_t len = 0;
    str = realloc(NULL, sizeof(*str)*size);//size is start size
    if(!str)return str;
    while(EOF!=(ch=fgetc(fp)) && ch != '\n'){
        str[len++]=ch;
        if(len==size){
            str = realloc(str, sizeof(*str)*(size+=16));
            if(!str)return str;
        }
    }
    str[len++]='\0';

    return realloc(str, sizeof(*str)*len);
}

int main(void){
    char *m;

    printf("input string : ");
    m = inputString(stdin, 10);
    printf("%s\n", m);

    free(m);
    return 0;
}

I've seen only one simple way of reading an arbitrarily long string, but I've never used it. I think it goes like this:

char *m = NULL;
printf("please input a string\n");
scanf("%ms",&m);
if (m == NULL)
    fprintf(stderr, "That string was too long!\n");
else
{
    printf("this is the string %s\n",m);
    /* ... any other use of m */
    free(m);
}

The m between % and s tells scanf() to measure the string and allocate memory for it and copy the string into that, and to store the address of that allocated memory in the corresponding argument. Once you're done with it you have to free() it.

This isn't supported on every implementation of scanf(), though.

As others have pointed out, the easiest solution is to set a limit on the length of the input. If you still want to use scanf() then you can do so this way:

char m[100];
scanf("%99s",&m);

Note that the size of m[] must be at least one byte larger than the number between % and s.

If the string entered is longer than 99, then the remaining characters will wait to be read by another call or by the rest of the format string passed to scanf().

Generally scanf() is not recommended for handling user input. It's best applied to basic structured text files that were created by another application. Even then, you must be aware that the input might not be formatted as you expect, as somebody might have interfered with it to try to break your program.

With the computers of today, you can get away with allocating very large strings (hundreds of thousands of characters) while hardly making a dent in the computer's RAM usage. So I wouldn't worry too much.

However, in the old days, when memory was at a premium, the common practice was to read strings in chunks. fgets reads up to a maximum number of chars from the input, but leaves the rest of the input buffer intact, so you can read the rest from it however you like.

in this example, I read in chunks of 200 chars, but you can use whatever chunk size you want of course.

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

char* readinput()
{
#define CHUNK 200
   char* input = NULL;
   char tempbuf[CHUNK];
   size_t inputlen = 0, templen = 0;
   do {
       fgets(tempbuf, CHUNK, stdin);
       templen = strlen(tempbuf);
       input = realloc(input, inputlen+templen+1);
       strcpy(input+inputlen, tempbuf);
       inputlen += templen;
    } while (templen==CHUNK-1 && tempbuf[CHUNK-2]!='\n');
    return input;
}

int main()
{
    char* result = readinput();
    printf("And the result is [%s]\n", result);
    free(result);
    return 0;
}

Note that this is a simplified example with no error checking; in real life you will have to make sure the input is OK by verifying the return value of fgets.

Also note that at the end if the readinput routine, no bytes are wasted; the string has the exact memory size it needs to have.