How to call Base Class's __init__ method from the child class?
You could use super(ChildClass, self).__init__()
class BaseClass(object):
def __init__(self, *args, **kwargs):
pass
class ChildClass(BaseClass):
def __init__(self, *args, **kwargs):
super(ChildClass, self).__init__(*args, **kwargs)
Your indentation is incorrect, here's the modified code:
class Car(object):
condition = "new"
def __init__(self, model, color, mpg):
self.model = model
self.color = color
self.mpg = mpg
class ElectricCar(Car):
def __init__(self, battery_type, model, color, mpg):
self.battery_type=battery_type
super(ElectricCar, self).__init__(model, color, mpg)
car = ElectricCar('battery', 'ford', 'golden', 10)
print car.__dict__
Here's the output:
{'color': 'golden', 'mpg': 10, 'model': 'ford', 'battery_type': 'battery'}
As Mingyu pointed out, there is a problem in formatting. Other than that, I would strongly recommend not using the Derived class's name while calling super()
since it makes your code inflexible (code maintenance and inheritance issues). In Python 3, Use super().__init__
instead. Here is the code after incorporating these changes :
class Car(object):
condition = "new"
def __init__(self, model, color, mpg):
self.model = model
self.color = color
self.mpg = mpg
class ElectricCar(Car):
def __init__(self, battery_type, model, color, mpg):
self.battery_type=battery_type
super().__init__(model, color, mpg)
Thanks to Erwin Mayer for pointing out the issue in using __class__
with super()
If you are using Python 3, it is recommended to simply call super() without any argument:
class Car(object):
condition = "new"
def __init__(self, model, color, mpg):
self.model = model
self.color = color
self.mpg = mpg
class ElectricCar(Car):
def __init__(self, battery_type, model, color, mpg):
self.battery_type=battery_type
super().__init__(model, color, mpg)
car = ElectricCar('battery', 'ford', 'golden', 10)
print car.__dict__
Do not call super with class as it may lead to infinite recursion exceptions as per this answer.